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soldier1979 [14.2K]
3 years ago
6

You are to design two CONCEPTUALLY different synchronous state machines (Mealy and Moore) that perform the task described below.

You are allowed to use any type of flip-flop. However, I recommend that you use either JK or D flip-flops. Win Announcer There is a game called screwball. Every time a ball is put into play either player 1 (P1) scores a point or player 2 (P2) scores a point. A winner is declared when one player is ahead by 2 points. Starting with a score of 0:0 forP1 vs. P2, a game might progress as follows:0:1 1:1 2:1 3:1 (P1 Wins!)
Design a finite state machine that uses information about which player scores a point at each stage of a game to determine when a player wins and which player wins. Your design should include one reset input to initialize your win announcer (this may be a synchronous or an asynchronous input, as you desire). The outputs from your designs should indicate BOTH when a win has occurred and which player is the winner?
Engineering
1 answer:
allochka39001 [22]3 years ago
3 0
Answer:








Explanation:









I hope this helps!
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11–17 A long, thin-walled double-pipe heat exchanger with tube and shell diameters of 1.0 cm and 2.5 cm, respectively, is used t
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the overall heat transfer coefficient of this heat exchanger is 1855.8923 W/m²°C

Explanation:

Given:

d₁ = diameter of the tube = 1 cm = 0.01 m

d₂ = diameter of the shell = 2.5 cm = 0.025 m

Refrigerant-134a

20°C is the temperature of water

h₁ = convection heat transfer coefficient = 4100 W/m² K

Water flows at a rate of 0.3 kg/s

Question: Determine the overall heat transfer coefficient of this heat exchanger, Q = ?

First at all, you need to get the properties of water at 20°C in tables:

k = 0.598 W/m°C

v = 1.004x10⁻⁶m²/s

Pr = 7.01

ρ = 998 kg/m³

Now, you need to calculate the velocity of the water that flows through the shell:

v_{w} =\frac{m}{\rho \pi (\frac{d_{2}^{2}-d_{1}^{2}  }{4} )} =\frac{0.3}{998*\pi (\frac{0.025^{2}-0.01^{2}  }{4}) } =0.729m/s

It is necessary to get the Reynold's number:

Re=\frac{v_{w}(d_{2}-d_{1}) }{v} =\frac{0.729*(0.025-0.01)}{1.004x10^{-6} } =10891.4343

Like the Reynold's number is greater than 10000, the regime is turbulent. Now, the Nusselt's number:

Nu=0.023Re^{0.8} Pr^{0.4} =0.023*(10891.4343)^{0.8} *(7.01)^{0.4} =85.0517

The overall heat transfer coefficient:

Q=\frac{1}{\frac{1}{h_{1} }+\frac{1}{h_{2} }  }

Here

h_{2} =\frac{kNu}{d_{2}-d_{1}} =\frac{0.598*85.0517}{0.025-0.01} =3390.7278W/m^{2}C

Substituting values:

Q=\frac{1}{\frac{1}{4100}+\frac{1}{3390.7278}  } =1855.8923W/m^{2} C

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3 years ago
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