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soldier1979 [14.2K]
3 years ago
6

You are to design two CONCEPTUALLY different synchronous state machines (Mealy and Moore) that perform the task described below.

You are allowed to use any type of flip-flop. However, I recommend that you use either JK or D flip-flops. Win Announcer There is a game called screwball. Every time a ball is put into play either player 1 (P1) scores a point or player 2 (P2) scores a point. A winner is declared when one player is ahead by 2 points. Starting with a score of 0:0 forP1 vs. P2, a game might progress as follows:0:1 1:1 2:1 3:1 (P1 Wins!)
Design a finite state machine that uses information about which player scores a point at each stage of a game to determine when a player wins and which player wins. Your design should include one reset input to initialize your win announcer (this may be a synchronous or an asynchronous input, as you desire). The outputs from your designs should indicate BOTH when a win has occurred and which player is the winner?
Engineering
1 answer:
allochka39001 [22]3 years ago
3 0
Answer:








Explanation:









I hope this helps!
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Clothing made of several thin layers of fabric with trapped air in between, often called ski clothing, is commonly used in cold
Pavlova-9 [17]

Answer:

Q=127.66W

L=9.2mm

Explanation:

Heat transfer consists of the propagation of energy in the form of heat in different ways, these can be convection if it is through a fluid, radiation through electromagnetic waves and conduction through solid solids.

To solve any problem related to heat transfer, the general equation is used

Q = delta / R

Where

Q = heat

Delta = the temperature difference

R = is the thermal resistance by conduction, convection and radiation

to solve this problem we propose the previous equation

Q = delta / R

later we find R

R=[tex]r=\frac{6L1}{AK1} +\frac{5L2}{AK2}+\frac{1}{Ah}

R=\frac{6(0.0001)}{(1.25)(0.026)} +\frac{5(0.012)}{(1.25)(0.026)}+\frac{1}{(25)(1.25)} =0.235 K/w

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part b

we use the same ecuation with Q=127.66

Q = delta / R

ΔR=\frac{L}{KA} +\frac{1}{hA} \\R=\frac{L}{(0.035)(1.25)} +\frac{1}{(25)(1.25)}\\ R=22.85L+0.032\\Q=(T1-T2)/R\\\\127.66=(25-(-5))/(22.85L+0.032)\\solving for L\\L=9.2mm

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