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kozerog [31]
3 years ago
13

The pictures below show samples of different substances.

Chemistry
2 answers:
zalisa [80]3 years ago
4 0

Answer:

C. Yes, if each sample contains 6.02 x 1023 atoms

Explanation: just got it correct on edge

Mrrafil [7]3 years ago
3 0

Answer:

C. Yes, if each sample contains 6.02 x 10²³ atoms.

Explanation:

It is possible for each sample to contain 1 mole of each sample if and only if each of the sample if made up of 6.02 x 10²³ atoms.

6.02 x 10²³ atoms is the Avogadro's number. This number is equivalent to a mole of a substance.

  • If the amount of matter in the given substance is at least one mole, it is possible that they are made up of one mole each of each substance.
  • If they contain lesser amount of atoms, then it is not up to one mole of substance.
  • But if it is greater, then, we can have even more than one mole of substance.

A mole is simply a unit of measurement and it is equivalent to 6.02 x 10²³ atoms.

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Which is a poor conductor of heat <br> a. aluminum<br> b. iron<br> c. ceramic<br> d. zinc
jasenka [17]

Answer:

c. ceramic

Explanation:

because b d and a are metals c is not

3 0
2 years ago
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A container with 3.0 moles of gas has a volume of 60.0L with a temperature at 400.K what is the pressure
iris [78.8K]

Answer: P= 1.64 atm

Explanation: solution attached.

Use Ideal gas law

PV= nRT

Derive for P

P= nRT/V R= 0.08205 L.atm/mol.K

Substitute the values.

3 0
3 years ago
2074 Set B Q.No. 1 What mass of nitrogen will be requires
timurjin [86]

140 g of nitrogen (N₂)

Explanation:

We have the following chemical equation:

N₂ + 3 H₂ -- > 2 NH₃

Now, to find the number of moles of ammonia we use the Avogadro's number:

if        1 mole of ammonia contains 6.022 × 10²³ molecules

then   X moles of ammonia contains 6.022 × 10²⁴ molecules

X = (1 × 6.022 × 10²⁴) / 6.022 × 10²³

X = 10 moles of ammonia

Taking in account the chemical reaction we devise the following reasoning:

If        1 mole of nitrogen produces 2 moles of ammonia

then  Y moles of nitrogen produces 10 moles of ammonia

Y = (1 × 10) / 2

Y = 5 moles of nitrogen

number of moles = mass / molecular weight

mass = number of moles × molecular weight

mass of nitrogen (N₂) = 5 × 28 = 140 g

Learn more about:

Avogadro's number

brainly.com/question/13772315

#learnwithBrainly

7 0
3 years ago
What is the best way to make sure graphs are easy to interpret
Neporo4naja [7]
<span>Use descriptive axis labels and legends
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7 0
3 years ago
Ethylenediamine (en) forms an octahedral complex with Ni2+(aq) with the formula [Ni(en)3]2+. Ni2+(aq) + 3 en ⇌ [Ni(en)3]2+(aq) K
yawa3891 [41]

Answer:

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

Explanation:

Ni^{2+}(aq) + 3 en\rightleftharpoons [Ni(en)_3]^{2+}(aq)

Concentration of nickel ion = [Ni^{2+}]=x

Concentration of nickel complex= [[Ni(en)_3]^{2+}]=\frac{0.16 mol}{2 L}=0.08 mol/L

Concentration of ethylenediamine = [en]=\frac{0.80 mol}{2 L}=0.40 mol/L

The formation constant of the complex = K_f=4.0\times 10^{18}

The expression of formation constant is given as:

K_f=\frac{[[Ni(en)_3]^{2+}]}{[Ni^{2+}][en]^3}

4.0\times 10^{18}=\frac{0.08 mol/L}{x\times (0.40 mol/L)^3}

x=\frac{0.08 mol/L}{4.0\times 10^{18}\times (0.40 mol/L)^3}

x=3.125\times 10^{-19} mol/L

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

6 0
3 years ago
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