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2 years ago

For the vaporization reaction Br2(l) → Br2(

1 answer:

3 0

The temperature at which the process be spontaneous is calculated as follows

delta G = delta H -T delta S

let delta G be =0

therefore delta H- T delta s =0

therefore T= delta H/ delta S
convert 31 Kj to J = 31 x1000= 31000 j/mol

T=31000j/mol /93 j/mol.k =333.33K

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If 50.0 g of silicon dioxide is heated with an excess of carbon, 27.9 g of silicon carbide is produced. What is the percent yiel

Molodets [167]

Answer: The percent yield of the reaction is 83.5 %

Explanation:

The given balanced equation is

$SiO_2+3C\rightarrow SiC+2CO$

$SiO_2$ is the limiting reagent as it limits the formation of product and $C$ is the excess reagent.

According to stoichiometry :

60.08 g of $SiO_2$ produce = 40.11 of $SiC$

Thus 50.0 of $SiO_2$ will produce= $\frac{40.11}{60.08}\times 50.0=33.4$ of $SiC$

Experimental yield of SiC = 27.9 g

Percent yield = $\frac{\text {Experimental yield}}{\text {theoretical yield}}\times 100=\frac{27.9g}{33.4g}\times 100=83.5\%$

Thus percent yield of the reaction is 83.5 %

6 0

2 years ago

Classify each molecule by whether its real bond angles are the same as or different than its model (ideal) bond angles. In other

blagie [28]

The question is incomplete; the complete question is: Classify each molecule by whether its real bond angles are the same as or different than its model (ideal) bond angles. In other words, do the bond angles change when you switch between Real and Model mode at the top of the page? Same (angles do not change) Different (angles change) Answer Bank | H2O | CO2, SO2, XeF2, BF3 CIF3, NH3, CH4, SF4, XeF4, BrF5, PCI5,SF6

Answer:

Compounds whose real bond angle are the same as ideal bond angle;

SF6, BF3, CH4, PCI5

Compounds whose real bond angles differ from ideal bond angles;

H2O, CO2, SO2, XeF2, CIF3, NH3, SF4, XeF4, BrF5

Explanation:

According to the valence shell electron pair repulsion theory (VSEPR), molecules adopt various shapes based on the number of electron pairs on the valence shell of the central atom of the molecule. The electron pairs usually orient themselves as far apart in space as possible leading to various observed bond angles.

The extent of repulsion of lone pairs is greater than that of bond pairs. Hence, the presence of lone pairs on the valence shell of the central atom in the molecule distorts the bond angles of molecules away from the ideal bond angles predicted on the basis of valence shell electron pair repulsion theory.

For instance, methane is a perfect tetrahedron having an ideal bond angle of 109°28'. Both methane and ammonia are based on a tetrahedron, however, the presence of a lone pair of electrons on nitrogen distorts the bond angle of ammonia to about 107°. The distortion of lone pairs in water is even more as the bond angles of water is about 104°.

5 0

2 years ago

HELP PLEASE !!!<br> Name the Salt formed When Nitric acid + Magnesium hydroxide

VladimirAG [237]

Answer:

magnesium chloride

Explanation:

Complete step-by-step answer:

The remaining ions combine to produce the salt of neutralisation. The salt is magnesium chloride. The chemical formula for the compound is $MgC{{l}_{2}}$.

8 0

2 years ago

What is the nature of the Ca-Cl bond in a molecule of calcium chloride (CaCl2) if the electronegativity value of calcium is 1.0

finlep [7]

Answer:

ionic

Explanation:

6 0

2 years ago

1) ΔS depends not merely on q but on ______ . Although there are many possible paths that could take a system from its initial t

Rus_ich [418]

Answer:

1) qrev/ reversible/ has only one particular value/ regardless of;

2) 1 mol of H₂(g) at 0ºC

3) a phase change/ remains constant/ increase

Explanation:

1) The change can occur in a reversible or an irreversible process. When the change is reversible, the system and the surroundings can be restored to their original state by exactly reversing the change. In an irreversible process, that is not possible.

The entropy variation (ΔS) is calculated only in the reversible process because, in the irreversible one, it's difficult to determine it. So, ΔS depends on qrev, which is the heat for the reversible process.

There is only one reversible isothermal path between two states, that's why it's easy to calculate ΔS for it.

The value of ΔS doesn't depend on the path, but only on the initial and the final states, so ΔS has only one particular value regardless of the path taken between states.

2) The entropy is the measure of the disorganization of a system, so when the molecules are more distant and vibrating, the entropy is higher (Sgas > Sliquid > Ssolid), and when the temperature increases, the entropy decreases (ΔS = qrev/T), so 1 mol of H₂(g) at 0ºC has the greatest entropy.

3) During a phase change, for a pure substance, the temperature remains constant, until all the substance changes for the other phase. The entropy is the measure of the disorganization of a system, so when the degrees of freedom and motion of the molecules increase, the system becomes more disorganized, so the entropy increases.

4 0

2 years ago