For the vaporization reaction Br2(l) → Br2(

1 answer:

3 0

The temperature at which the process be spontaneous is calculated as follows

delta G = delta H -T delta S

let delta G be =0

therefore delta H- T delta s =0

therefore T= delta H/ delta S
convert 31 Kj to J = 31 x1000= 31000 j/mol

T=31000j/mol /93 j/mol.k =333.33K

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