They are all related to what time of year it is.
Answer:
total distance = 1868.478 m
Explanation:
given data
accelerate = 1.68 m/s²
time = 14.2 s
constant time = 68 s
speed = 3.70 m/s²
to find out
total distance
solution
we know train start at rest so final velocity will be after 14 .2 s is
velocity final = acceleration × time ..............1
final velocity = 1.68 × 14.2
final velocity = 23.856 m/s²
and for stop train we need time that is
final velocity = u + at
23.856 = 0 + 3.70(t)
t = 6.44 s
and
distance = ut + 1/2 × at² ...........2
here u is initial velocity and t is time for 14.2 sec
distance 1 = 0 + 1/2 × 1.68 (14.2)²
distance 1 = 169.37 m
and
distance for 68 sec
distance 2= final velocity × time
distance 2= 23.856 × 68
distance 2 = 1622.208 m
and
distance for 6.44 sec
distance 3 = ut + 1/2 × at²
distance 3 = 23.856(6.44) - 0.5 (3.70) (6.44)²
distance 3 = 76.90 m
so
total distance = distance 1 + distance 2 + distance 3
total distance = 169.37 + 1622.208 + 76.90
total distance = 1868.478 m
I would think B, Position, direction and speed. I tried looking it up and B seems to be the closest answer that resembles my results as I found that energy didn’t describe the motion of an object.
The two things that must exist for an electric current to be produced are:
An electric potential between two bodies and a conducting path joining the bodies.
This comes from the fact that when there is a potential difference there is an electrical field and hence a force that makes some free charges to move in the conductor. For this reason, there's an electrical current.
The maximum height of the object when thrown at the speed of 20 m/s is 20 m.
What is speed?
Speed is the magnitude of the rate of change of the position of any object with time which is a scalar quantity. It is the ratio of speed by time with the unit m/s or cm/s.
The height this object can travel with initial speed of 20 m/s can be calculated as,
<u>v^2 = u^2 + 2as</u>
where v is the final velocity, u is the initial velocity a is the acceleration due to gravity s is height.
0 = 20^2 + 2 (-10) s
s = 400 / 20 = 20 m
Therefore, the maximum height the object can travel with initial speed of 20 m/s is 20m.
To learn more about the speed click on the given link brainly.com/question/13943409
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