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mestny [16]
2 years ago
11

The three notches in the graph occur where the driver changed gears. Describe the changes in velocity and acceleration of the ca

r while in first gear. Is the acceleration just before a gear change larger or smaller than the acceleration just after the change?
Explain your answer
Physics
1 answer:
kaheart [24]2 years ago
6 0
<h3>Answer : </h3><h3 /><h3>A ) The larger gear can be moved by applying a relatively small force on the smaller gear.</h3>

<h3>B ) The force applied on the smaller gear is transmitted without any loss to the larger gear .</h3><h3 /><h3>C ) the direction of motion can be changed without changing the direction of the applied force .</h3>

D ) the system would continue to move without any further, after and initial force has set in motion.

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What does an unconformity in a sequence of rock layers reveal about geologic history?
andreev551 [17]
An unconformity, or abnormality in the layers of rocks, signifies that the process of layering was somehow interrupted. The only feasible choice for this would be (B), where erosion would have interrupted the layering process.
7 0
3 years ago
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A helium-filled balloon is launched when the temperature at ground level is 27.8°c and the barometer reads 752 mmhg. if the ball
ololo11 [35]
The helium may be treated as an ideal gas, so that
(p*V)/T =constant
where
p = pressure
V = volume
T = temperature.

Note that
7.5006 x 10⁻³ mm Hg = 1 Pa
1 L = 10⁻³ m³

Given:
At ground level,
p₁ = 752 mm Hg
     = (752 mm Hg)/(7.5006 x 10⁻³ mm Hg/Pa)
     = 1.0026 x 10⁵ Pa
V₁ = 9.47 x 10⁴ L = (9.47 x 10⁴ L)*(10⁻³ m³/L)
     = 94.7 m³
T₁ = 27.8 °C = 27.8 + 273 K
     = 300.8 K

At 36 km height,
P₂ = 73 mm Hg = 73/7.5006 x 10⁻³ Pa
     = 9.7326 x 10³ Pa
T₂ = 235 K

If the volume at  36 km height is V₂, then
V₂ = (T₂/p₂)*(p₁/T₁)*V₁
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Answer: 762.2 m³  
3 0
3 years ago
The diagram below shows a boat moving north in a river at 3m/s while the current in the river moves south at 1 m/s.
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Answer it will move slower:

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2 years ago
300 Jules energy are used to push an object with a force of 75N. what is the maximum distance the object can move?
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Energy consumed in doing the work = 300 Joules

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Let the distance moved by the object be d.

Work done by the force is determined by the force applied and the displacement happened in the direction of the force applied.

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300 = 75 x d

d = \frac{300}{75}

d = 4 m

Hence, the maximum distance moved by the object = 4 meters

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3 years ago
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horsena [70]
0 miles from where you started
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