1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Crank
3 years ago
6

How much power is expended if you lift a 60 n crate 10 meters in 1 second?

Physics
1 answer:
Murljashka [212]3 years ago
3 0

It's P =W/t is equation 1 . Since W=F×S.. put it in equation 1 ,we get P=FS/t. Put F =60N , S=10m and time =1 s in equation 1. Then we have P=60×10/1s which is 600 Watts. So power of the body is 600Watts
You might be interested in
I need help with this question how to solve it for Brass and Cooper
Ksenya-84 [330]

Take into account that density and relative density are given by:

\begin{gathered} \text{density}=\text{ mass/volume} \\ \text{relative density = density/density of water} \end{gathered}

Take into account that the volume associated to each of the given sustances in the table is determined by the Level Difference (because it is the change in the volume of the water of the recipient in which the substance is immersed).

The density of water in kg/m^3 is 1000 kg/m^3.

Due to the density must be given in kg/m^3, it is necessary to express the volumes of the table in m^3 and mass in kg, then, consider the following conversion factor:

1 m^3 = 1000000 ml

1 kg = 1000 g

Then, you obtain the following results:

Brass:

\begin{gathered} 53.2g\cdot\frac{1kg}{1000g}=0.0532kg \\ 6ml\cdot\frac{1m^3}{1000000ml}=0.000006m^3 \\ \text{density}=\frac{0.0532kg}{0.000006m^3}\approx8866.67\frac{kg}{m^3} \\ \text{relative density=}\frac{(\frac{8866.66kg}{m^3})}{(1000\frac{kg}{m^3})}\approx8.87 \end{gathered}

Cooper:

\begin{gathered} 57.4g=0.0574kg \\ 6ml=0.000006m^3 \\ \text{density}=\frac{0.0574kg}{0.000006m^3}\approx9566.67\frac{kg}{m^3} \\ \text{relative density=}\frac{\frac{9566.67kg}{m^3}}{1000kg}=9.57 \end{gathered}

3 0
1 year ago
The length of the student desk is measured using a
charle [14.2K]

Answer:

3 significant figures are in 1.02m

Explanation:

4 0
3 years ago
A. Which of the four thermal processes describes the pressure-volume relationship at a constant temperature?
zhannawk [14.2K]
Boyles law describes pressure volume relationship at constant temperature  pressure is directly proportional  to volume at constant tamparature
4 0
3 years ago
Read 2 more answers
In order for a ball to move upward, the initial velocity of the ball must be greater than _____.
ch4aika [34]

Answer:

The answer is zero please Give me Brainly

Explanation:

5 0
2 years ago
A force of 4 kg weight acts on a body of mass 9.8 kg calculate the acceleration
White raven [17]

Answer:

here given is a weight

then force becomes mg

that is F=Mg

=4*9.8

then by using the formula

F=Ma

a=F/M

=4*9.8/9.8

=4

Explanation:

3 0
3 years ago
Read 2 more answers
Other questions:
  • A single slit is illuminated by light of wavelengths λa and λb, chosen so that the first diffraction minimum of the λa component
    9·1 answer
  • How does density of the medium affect the speed of a wave?
    6·1 answer
  • A 40.0-$kg$ body is moving in the direction of the positive x axis with a speed of 238 $m/s$ when, owing to an internal explosio
    10·1 answer
  • A packing crate is sitting at rest on an inclined loading ramp. How does the magnitude of the force of static friction compare t
    10·1 answer
  • Select the correct images.
    8·2 answers
  • In terms of their location, what is the difference between subcutaneous fat and visceral fat
    7·1 answer
  • Check the photo and try me help​
    11·1 answer
  • Pls give motivation, a paragraph pls! I'll give brainliest to whoever's is the biggest and best! I'll give 50 points, it is for
    13·1 answer
  • An object moves with constant velocity .<br><br> •1st law<br> •2nd law
    7·1 answer
  • What is your worldview? Explain?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!