All categories

3 years ago

How do you find average velocity during free fall?

Physics

2 answers:

Genrish500 [490]3 years ago

6 0

The sum of the initial and final velocity divided by 2.

Gekata [30.6K]3 years ago

6 0

- 400 all over 5 minus 0 which is negative 400 minus 5 which is going to be negative 80 feet perMore

You might be interested in

A person of mass 75 kg stands at the center of a rotating merry-go-round platform of radius 3.3 m and moment of inertia

vivado [14]

Answer:

(a) 0.426 rad/s

(b) Before 296.225 J and After 148.5 J

Explanation:

At the center of merry-go-round, the person's weight is 75 Kg with moment of inertia of 820 kgm2 and the initial angular velocity is 0.85 rad/s

At the edge, the new angular velocity gained depends on the new moment of inertia

Here, the final moment of inertia is given by Initial moment of inertia + $MR^{2}$ where M is the mass and R is the radius of merry-go-round

Final moment of inertia= $820+(75*3.3^{2})=1636.75$

From the law of conservation of angular momentum as torque is zero

$I_i\times\omega_1=I_f\times\omega_2$ and making $\omega_2$ the subject then

$\omega_2=\frac {I_i\times\omega}{I_f}$

where $I_i$ and $I_f$ are initial and final moment of inertia, $\omega_1$ and $\omega_2$ are initial and final angular velocity.

Substituting the provided values

$\omega_2=\frac {0.85\times 820}{1636.75}=0.425843898\approx 0.426 rad/s$

(b)

Initial rotational kinetic energy is given by

$0.5I_i\times \omega_1^{2}$

$KE_i=0.5\times 820\times 0.85^{2}=296.225 J$

The final rotational kinetic energy is given by

$0.5I_f\times \omega_2^{2}$

$KE_i=0.5\times 1636.75\times 0.426^{2}\approx 148.5 J$

7 0

4 years ago

a 7.26kg bowling ball (16 pounds) is at rest at the end of the bowling lane. : how long did you push the ball in this situation

nlexa [21]

Let F be the force acting on the bowling ball.

Work done by force= change in KE

Let F be the force acting on the bowling ball

Work done by force = change in KE

F .d = 0.5 m V^2 + 0.5 x I x w^2

F d = 0.5 m ( 1+l) V^2

Solve accordingly to get the answer.

6 0

3 years ago

Compare and contrast an electric discharge with an electric current

vlabodo [156]

The electric current<span> is the number of electrons or charges passing through a conductor per units of time. 1 ampere = 1 coulombs / 1 second. </span>Electric discharge <span>is the consequence of disrupting an isolator (for example, air), thus causing a sudden flow of </span><span>electricity</span>

3 0

4 years ago

30) A force produces power P by doing work W in a time T. What power will be produced by a force that does six times as much wor

schepotkina [342]

Answer:

A) 12P

Explanation:

The power produced by a force is given by the equation

$P=\frac{W}{T}$

where

W is the work done by the force

T is the time in which the work is done

At the beginning in this problem, we have:

W = work done by the force

T = time taken

So the power produced is

$P=\frac{W}{T}$

Later, the force does six times more work, so the work done now is

$W'=6W$

And this work is done in half the time, so the new time is

$T'=\frac{T}{2}$

Substituting into the equation of the power, we find the new power produced:

$P'=\frac{W'}{T'}=\frac{6W}{T/2}=12\frac{W}{T}=12P$

So, 12 times more power.

4 0

3 years ago

Why is it incorrect to say that astronauts are weightlesS in space while orbiting Earth in a space shuttle?

Mamont248 [21]

This is because Gravity exists everywhere in the universe.

<h3>What is Gravity?</h3>

This is the force of attraction which acts on all matters in the universe. Astronauts appear weightless while in orbiting the Earth because the space shuttle and the astronauts are in free fall around it.

They fall at the same rate as the space shuttle which is why the astronauts appear weightless.

Read more about Gravity here brainly.com/question/88039

6 0

2 years ago