Answer:
x = 13
Step-by-step explanation:
x =
12^2 + 5^2 = 13
<span>this your answer hun
</span><span>P ( canadian)= 3/15 = 1/5
-> P(not canadian) = 1 - 1/5 = 4/5</span>
Answer:
Area under the normal curve: 0.6915.
69.15% probability of putting less than 24 ounces in a cup.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
You have been asked to calculate the probability of putting less than 24 ounces in a cup.
pvalue of Z when X = 24. So
has a pvalue of 0.6915
Area under the normal curve: 0.6915.
69.15% probability of putting less than 24 ounces in a cup.
Answer:
the answer is 48
but because there is -6 the answer will be -48
The required mean height of the ocean at first high tide is 1.81 meters. Option A is correct.
Given that,
The list below shows the height, in meters, of an ocean's first high tide for each of 6 days.
Number of days = 1 2 3 4 5 6 Total = 6
1.72 1.8 1.86 1.88 1.74 1.86
<h3>
What is average?</h3>
The average of the values is the ratio of the total sum of values to the number of values.
Since the mean of the heights of the tides,
= sum of heights / number of heights observation
= (1.7 + 1.8 + 1.86 + 1.88 + 1.74 + 1.86)/6
= 10.86/6
= 1.81 meters
Thus, the required mean height of the ocean at first high tide is 1.81 meters. Option A is correct.
Learn more about average here:
brainly.com/question/24057012
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