Answer:
C
Explanation:
The pattern is adding .5 to the cm every .1 in weight you just continue the table
2.5 miles an hour but yea hope that helps
Explanation:
The charge on the electron is, ![q=-1.6\times 10^{-19}\ C](https://tex.z-dn.net/?f=q%3D-1.6%5Ctimes%2010%5E%7B-19%7D%5C%20C)
The electric field at a distance r from the electron is :
![E=k\dfrac{q}{r^2}](https://tex.z-dn.net/?f=E%3Dk%5Cdfrac%7Bq%7D%7Br%5E2%7D)
Where
k is the electrostatic constant, ![k=\dfrac{1}{4\pi \epsilon_o}](https://tex.z-dn.net/?f=k%3D%5Cdfrac%7B1%7D%7B4%5Cpi%20%5Cepsilon_o%7D)
We know that the electric field lines starts from positive charge and ends at the negative charge. Also, for a positive charge the field lines are outwards while for a negative charge the field lines are inwards.
So, the correct option is " the electric field is directed toward the electron and has a magnitude of
. Hence, this is the required solution.
Answer:
f = 2858.33 Hz
Explanation:
given,
distance between speaker (A) and the person = 2.34 m
Distance between speaker (B) and the person is AB =
=![\sqrt{(0.764)^2 + (2.34)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%280.764%29%5E2%20%2B%20%282.34%29%5E2%7D)
= 2.46 m
path difference d = BP - AP
= 2.46 - 2.34 m
= 0.12 m
now, λ = 0.12
speed of sound = 343 m/s
![f= \dfrac{c}{\lambda}](https://tex.z-dn.net/?f=f%3D%20%5Cdfrac%7Bc%7D%7B%5Clambda%7D)
![f= \dfrac{343}{0.12}](https://tex.z-dn.net/?f=f%3D%20%5Cdfrac%7B343%7D%7B0.12%7D)
f = 2858.33 Hz
the lowest frequency that will produce constructive interference is equal to
f = 2858.33 Hz
Answer:
ω = 0.36 rev/s = 2.24 rad/s
Explanation:
First, we will find the time taken by the diver to reach the water. For this we use 2nd equation of motion:
h = Vi t + (1/2)gt²
where,
h = height = 9.6 m
Vi = initial vertical velocity = 0 m/s
t = time taken = ?
g = 9.8 m/s²
Therefore,
9.6 m = (0 m/s)(t) + (1/2)(9.8 m/s²)t²
t = √1.95 s²
t = 1.4 s
Now, the average angular speed of diver will be:
ω = No. of Revolutions/t
ω = 0.5 rev/1.4 s
<u>ω = 0.36 rev/s = 2.24 rad/s</u>