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PilotLPTM [1.2K]
3 years ago
6

Nuclear forces exists because the particles in the nucleus are ?

Chemistry
1 answer:
zloy xaker [14]3 years ago
8 0

Explanation:

Nuclear forces exist because the particles in the nucleus are close together the tritium atom consists of one proton, two neutron, and one electron how many isotopes of hydrogen are known 3 The hydrogen isotope with the least mass is named protium

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The air inside a bicycle tire pump has 27 joules of heat conducted away from while 77.9 joules of work done are being done on it
tatyana61 [14]

Answer:

51 J

Explanation:

The air inside a bicycle tire pump has 27 joules of heat conducted away. By convention, when heat is released, it takes the negative sign, so Q = -27 J.

77.9 joules of work done are being done on the air inside a bicycle tire pump. By convention, when work is being done on the system, it takes the positive sign, so W = 77.9 J

We can calculate the change in the internal energy (ΔU) using the following expression.

ΔU = Q + W

ΔU = (-27 J) + 77.9 J

ΔU =  51 J

7 0
3 years ago
A substance is tested and has a pH of 7.0. How would you classify it?
Alexandra [31]

Answer:

C

Explanation:

The substance would be classified as neutral, so C.

5 0
3 years ago
Read 2 more answers
The combustion of glucose (c6h12o6) with oxygen gas produces carbon dioxide and water. this process releases 2803 kj per mole of
V125BC [204]

Answer:- 335 kcal of heat energy is produced.

Solution:- The balanced equation for the combustion of glucose in presence of oxygen to give carbon dioxide and water is:

C_6H_1_2O_6+6O_2\rightarrow 6CO_2+6H_2O

From given info, 2803 kJ of heat is released bu the combustion of 1 mol of glucose. We need to calculate the energy produced when 3.00 moles of oxygen react with excess of glucose.

We could solve this using dimensional analysis as:

3.00mol O_2(\frac{1mol glucose}{6mol O_2})(\frac{2803 kJ}{1mol glucose})

= 1401.5 kJ

Now, let's convert kJ to kcal.

We know that, 1kcal = 4.184kJ

So, 1401.5kJ(\frac{1kcal}{4.184kJ})

= 335 kcal

Hence, 335 kcal of heat energy is produced by the use of 3.00 moles of oxygen gas.


8 0
3 years ago
What volume of a 1.0 M HCl is required to completely neutralize 25.0 ml of a 1.0 M KOH?
kirza4 [7]
The question above can be solved by using this equation: 
CAVA =CBVB
Where:
CA =Concentration of acid = 1.0 M
VA = Volume of acid = ?
CB = Concentration of base = 1.0 M
VB = Volume of base = 25 ml
VA = CBVB / CA
VA = [1 * 25] / 1 = 25 / 1 = 25
VA = 25 ml
Therefore, the volume of acid that is required to completely neutralize the base is 25 ml.<span />
8 0
3 years ago
14
Bond [772]

Answer:

Explanation:

The melting point of a substance is the temperature at which its melt. The state of a substance is dependent on it's melting temperature. Generally, melting point above 25 °C is a solid.

This means phenol is a solid

Duodecane has melting point below 25 °C hence it is either a liquid or gas. However its boiling point of 216 °C means it would require higher temperature to boil it. Since 25 °C is less than 216 °C it means that it would remain in the liquid state.

Methane has melting point below 25 °C hence it is either a liquid or gas. However its boiling point of -164 °C means it boils easily even at very low temperatures. Since 25 °C is greater than -164 °C it means that it would exist in the gaseous state

8 0
3 years ago
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