<span>Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d. -18, -81, -144
Solution:
Since it has to be between -13 and 89, letter d and b are not anymore considered to be the answer.
for a:
33-(-13)=46=d
43-33=10=d the value for this d is different from the two sequence,
89-43=46=d
they have different value for d, thus this is not the answer!
for c:
21-(-13)=34=d
55-21=34=d
89-55=34=d
they have the same value for d, thus the correct answer is </span><span> c. -13, 21, 55, 89</span>
Solve for x:
x^9 = n x
Subtract n x from both sides:
x^9 - n x = 0
Factor x and constant terms from the left hand side:
-x (n - x^8) = 0
Multiply both sides by -1:
x (n - x^8) = 0
Split into two equations:
x = 0 or n - x^8 = 0
Subtract n from both sides:
x = 0 or -x^8 = -n
Multiply both sides by -1:
x = 0 or x^8 = n
Taking 8^th roots gives n^(1/8) times the 8^th roots of unity:
Answer: x = 0 or x = -n^(1/8) or x = -i n^(1/8) or x = i n^(1/8) or x = n^(1/8) or x = -(-1)^(1/4) n^(1/8) or x = (-1)^(1/4) n^(1/8) or x = -(-1)^(3/4) n^(1/8) or x = (-1)^(3/4) n^(1/8)
Answer:
The area is: 
, option b.
Step-by-step explanation:
Rectangular area:
The area of a rectangular space is given bt the multiplication of its measures.
Area of the roof:
Dimensions of 10x + 8 and 8x + 6. So
Area of the skylight:
Dimensions of x + 5 and 3x + 4. So
What is the area of the remaining roof after the skylight is built?
Total subtracted by the skylight, which is a subtraction of a polynomial, in which we subtract the like terms. So
The area is: , option b.
3(-3 + 5x) -1 (4 - 4x)
Simplify each term by first using the distributive property with each set of parenthesis:
3*-3 + 3*5x - 1*4 -1* -4x
Now do the multiplications:
-9 + 15x -4 + 4x
Combine like terms
15x +4x - 9 -4
19x - 13
You subtract 200 by 80 and your answer would be 120 people are women
