Answer:
a
e(k) = \frac{2a}{c} * sin (\frac{k*a}{2} )
b
G_{v} = \frac{d e(k ) }{dk } = \frac{a^2}{c} * cos (\frac{k* a}{2} )
Explanation:
From the question we are told that
The velocity of transverse waves in a crystal of atomic separation is
Generally the dispersion relation is mathematically represented as
=>
=>
=>
Generally the group velocity is mathematically represented as
Answer:
U(0.0m) = 0J
U(5.5m) = 40.42 J
Explanation:
The gravitational potential energy is given by the following formula:
h: height
m: mass of the apple = 0.75kg
g: gravitational acceleration = 9.8m/s^2
When the apple is at 5.5m from the ground the gravitational potential energy is:
when the apple is on the ground you have:
Answer:
Option D) -0.0707
Explanation:
We are given the following in the question:
Population mean, μ = 45 mp
Sample mean, = 44.9
Sample size, n = 50
Sample standard deviation, s = 10
Formula:
Putting all the values, we have
Thus, the test statistic is
Option D) -0.0707