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elena-s [515]
3 years ago
10

A force of 90N is applied to each cart below, which one will accelerate the fastest?

Physics
2 answers:
Finger [1]3 years ago
8 0
5kg, this is because it ways the least which means it will move easier
siniylev [52]3 years ago
5 0

Answer:

5kg

Explanation:

The cart with the least amount of mass will result in the fastest acceleration.

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Assume that segment r exerts a force of magnitude t on segment l. what is the magnitude flr of the force exerted on segment r by
mrs_skeptik [129]
If we are talking on the force being exerted by a segment of a rope of lenght R on the right on a point M which is being also pulled from the Left by a segment of rope R  as shown in the figure attached. Then we invoke Newton's Third Law:
"Any force exerted by an object (in this case a segment of the rope) also suffers a equal and opposite force".
If we pick T_R=T whis is the tension exerted by the right segment then the left segment will also exert an equal and opposite force so we have that T_L=-T

8 0
3 years ago
Which elements has the smallest first ionization energy?
Setler [38]

Answer:

Cesium has smallest ionization energy.

Explanation:

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H ⇒ H^{+} + e^{-}

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Therefore the cesium has smallest ionization energy.

8 0
4 years ago
The amount of momentum that an object has is dependent on what ____ is moving and how ___ it is moving.
ivann1987 [24]
P=mv
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5 0
3 years ago
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The normal force of a parked car is 15,000 Newtons. The coefficient of static friction between the rubber of the tires and the a
Shtirlitz [24]

Answer:

11250 N

Explanation:

From the question given above, the following data were obtained:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

Friction and normal force are related by the following equation:

F = μR

Where:

F is the frictional force.

μ is the coefficient of static friction.

R is the normal force.

With the above formula, we can calculate the frictional force acting on the car as follow:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

F = μR

F = 0.75 × 15000

F = 11250 N

Therefore, the frictional force acting on the car is 11250 N

3 0
3 years ago
6. The four main systems of the Earth are
nevsk [136]
Geosphere, hydrosphere, atmosphere, and biosphere.

Therefore, the correct answer is D.
8 0
3 years ago
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