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Nana76 [90]
3 years ago
12

electromagnetic waves of wavelengths 1,34nm are emitted. how much energy do photons of this light have​

Physics
1 answer:
Sergio039 [100]3 years ago
8 0

Answer:

energy =  \frac{planck  \: const.\:  \times speed \: of \: light}{wavelength}

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2) A swinging motion of a Pendulum of clock is _______
VashaNatasha [74]

Oscillatory motion.(also known as Periodic motion)

Hope it helps...

Regards,

Leukonov/Olegion.

3 0
3 years ago
Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. If the surface charg
bekas [8.4K]

Answer:

5.3\times 10^3 N/C

Explanation:

We are given that

Distance between plates=d=2.2 cm=2.2\times 10^{-2} m

1 cm=10^{-2} m

\sigma=47nC/m^2=47\times 10^{-9}C/m^2

Using 1 nC=10^{-9} C

We have to find the magnitude of E in the region between the plates.

We know that the electric field for parallel plates

E=\frac{\sigma}{2\epsilon_0}

E_1=\frac{\sigma}{2\epsilon_0}

E_2=\frac{\sigma}{2\epsilon_0}

E=E_1+E_2

E=\frac{\sigma}{2\epsilon_0}+\frac{\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}

Where \epsilon_0=8.85\times 10^{-12}C^2/Nm^2

Substitute the values

E=\frac{47\times 10^{-9}}{8.85\times 10^{-12}}

E=5.3\times 10^3 N/C

Hence, the magnitude of E in the region between the plates=5.3\times 10^3 N/C

5 0
3 years ago
A certain helium-neon laser pointer, emitting light with a wavelength of 632 nm, has a beam with an intensity of 825 W/m2 and a
BabaBlast [244]

Answer:

N = 1.62 \times 10^{15}

Explanation:

Energy of each photon is given as

E = \frac{hc}{\lambda}

here we will have

\lambda = 632 nm

now we will have

E = \frac{(6.626\times 10^{-34})(3 \times 10^8)}{632 \times 10^{-9}}

E = 3.14 \times 10^{-19} J

now let say there is N number of photons per second

so power due to photons is

P = N(3.14 \times 10^{-19})

now intensity is given as power received per unit area

so we have

I = \frac{P}{A}

825 = \frac{N(3.14 \times 10^{-19})}{\pi (1.40 \times 10^{-3})^2}

825 = N(5.11 \times 10^{-14})

N = 1.62 \times 10^{15}

5 0
3 years ago
A 30 N rightward force is exerted on a 7 kg object. There is a 3 N force of friction acting on the object. What is the Weight of
IgorLugansk [536]

Answer:

W = 68.6 N

Explanation:

Given that,

Force acting on a right side = 30 N

Mass of the object, m = 7 kg

The force of friction acting on the car = 3 N

We need to find the weight of the object.

The weight of an object is given by :

W = mg

Substitute all the values,

W = 7 × 9.8

W = 68.6 N

So, the weight of the object is 68.6 N.

6 0
3 years ago
A rock is dropped from the top of a tower. When it is 40 meters above the ground velocity of 17 m/s. When its velocity is 24 m/s
eimsori [14]

Answer:

Option B is the correct answer.

Explanation:

Let us consider 40 meter above ground as origin.

Initial velocity = 17 m/s

Final velocity = 24 m/s

Acceleration = 9.81 m/s

We have equation of motion v² = u² + 2as

Substituting

         24² = 17² + 2 x 9.81 x s

           s = 14.63 m

Distance traveled by rock = 14.63 m down.

Height of rock from ground = 40 - 14.63 = 25.37 m = 25.4 m

Option B is the correct answer.

4 0
4 years ago
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