Oscillatory motion.(also known as Periodic motion)
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Regards,
Leukonov/Olegion.
Answer:

Explanation:
We are given that
Distance between plates=d=2.2 cm=


Using 
We have to find the magnitude of E in the region between the plates.
We know that the electric field for parallel plates





Where 
Substitute the values


Hence, the magnitude of E in the region between the plates=
Answer:

Explanation:
Energy of each photon is given as

here we will have

now we will have


now let say there is N number of photons per second
so power due to photons is

now intensity is given as power received per unit area
so we have




Answer:
W = 68.6 N
Explanation:
Given that,
Force acting on a right side = 30 N
Mass of the object, m = 7 kg
The force of friction acting on the car = 3 N
We need to find the weight of the object.
The weight of an object is given by :
W = mg
Substitute all the values,
W = 7 × 9.8
W = 68.6 N
So, the weight of the object is 68.6 N.
Answer:
Option B is the correct answer.
Explanation:
Let us consider 40 meter above ground as origin.
Initial velocity = 17 m/s
Final velocity = 24 m/s
Acceleration = 9.81 m/s
We have equation of motion v² = u² + 2as
Substituting
24² = 17² + 2 x 9.81 x s
s = 14.63 m
Distance traveled by rock = 14.63 m down.
Height of rock from ground = 40 - 14.63 = 25.37 m = 25.4 m
Option B is the correct answer.