electromagnetic waves of wavelengths 1,34nm are emitted. how much energy do photons of this light have

Physics

1 answer:

Sergio039 [100]2 years ago

8 0

Answer:

$energy = \frac{planck \: const.\: \times speed \: of \: light}{wavelength}$

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A 5c charge experiences a force of 40n when put at a certain location in space. What is the electric field at that location?

stepladder [879]

The 'strength' of the electric field is the force on 1C of charge at that point.

At this 'certain location', the field is 40/5 = 8 newtons per coulomb = <u>8 volts</u>

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3 years ago

Indicate whether the statement is true or false. A force can be simply defined as a push or a pull.

Sidana [21]

This B: False, because the definition is lacking.

Force is when two objects interact with one another causing it to either move or not move. In our daily lives there are a lot of times force is exerted upon us, rather force is everywhere and here are the evidences:

*Pushing a cart
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*Hitting a baseball bat
*Apple falling down from a tree.
*Balls hitting one another
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3 years ago

Because the earth's orbit is slightly elliptical, the earth actually gets closer to the sun during part of the year. When the ea

BabaBlast [244]

Closer to the sun . . . orbital speed is faster.

Farther from the sun . . . orbital speed is slower.

Flag answer: Answer 13 Answer 13

5 0

2 years ago

Two objects separated by a distance r are each carrying a charge q The magnitude of the force exerted on the second object by th

Sindrei [870]

Answer:F=4F

Explanation: Columbs law states that The force between the two point charges is directly proportional to the product of charges and inversely proportional to the square of distance between them

Force between the two charges is given by

F=K*q1*q2/r^2

if one charge become 4 times, new force is,

F=4(K*q1*q2)/r^2

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If an object is to rest on an incline without slipping, then friction must equal the component of the weight of the object paral

leonid [27]

Answer:

$\theta = tan^{-1}\mu$

Explanation:

As we know that if the object is placed on the inclined plane then the force of friction on the object is counterbalanced by the component of the weight of the object along the inclined plane.

So we can say

$F_f = mgsin\theta$

now if we increase the inclination of the plane then the component of the weight weight along the inclined plane will increase and hence the friction force will also increase.

As we know that the limiting value or the maximum value of friction force at the static condition is given by

$F_f = \mu N$