All categories

2 years ago

What is the main function of a telescope?

Physics

2 answers:

love history [14]2 years ago

8 0

Explanation :

Telescope is an instrument which is used to magnify distant objects bright, consistent and large.

The function of an ideal telescope must be :

Magnification
Resolution
Power of gathering of light

There are many types of Telescope like:

X ray telescope
Optical telescope
Ultraviolet telescope etc

Hence, the correct option is (b) " It magnifies light received from distant objects ".

Korvikt [17]2 years ago

4 0

It magnifies light received from distant objects.

You might be interested in

It took Lightning McGreen 2.5 hours to travel

Law Incorporation [45]

Answer:

240km/h

Explanation:

speed=distance/time

speed=600/2.5

=240km/h

4 0

2 years ago

Read 2 more answers

A power plant produces 1000 MW to suply a city 40Km away.Current flows from the power plant on a single wire of resistance0.050

Westkost [7]

Answer:

The current in wire resistance 2Ω

a). 8696 A

b). fraction power 15.1% a 115kV

Explanation:

Resistance

$R=0.05$ Ω/Km*40km

R=2Ω

P=1000 MW

a).

$P=V*I\\I=\frac{P}{V}=\frac{1000x10^{6}W}{115x10^{3}k } =8696.65A$

Using law ohm

b).

$V=I*R\\I=\frac{V}{R}$

$P=I*I*R\\P=I^{2} *R\\P=8696.65^{2}*2\\P=151.228 x10^{6} W$

$e=\frac{151.228x10^{6} }{1000x10^{6} }*100= 15.12$ %

8 0

3 years ago

Which of the five themes of geography would a person most likely use to study the importation of Chinese goods into the United S

Morgarella [4.7K]

B. Movement would be the correct answer.

7 0

2 years ago

the physics concept corresponding to oomph is momentum. building on your above answers, figure out a formula for momentum (oomph

topjm [15]

Momentum = mass * velocity

I need parts A and B to explain the intuitions.

7 0

2 years ago

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton

pishuonlain [190]

Hello!

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.

Data:

Hooke represented mathematically his theory with the equation:

F = K * Δx

On what:

F (elastic force) = 2 N

K (elastic constant) = 4 N/cm

Δx (deformation or elongation of the elastic medium or distance from a spring) = ?

Solving:

$F = K * \Delta{x}$

$2\:N = 4\:N/cm*\Delta{x}$

$4\:N/cm*\Delta{x} = 2\:N$

$\Delta{x} = \dfrac{2\:\diagup\!\!\!\!\!N}{4\:\diagup\!\!\!\!\!N/cm}$

simplify by 2

$\Delta{x} = \dfrac{2}{4}\frac{\div2}{\div2}$

$\boxed{\boxed{\Delta{x} = \dfrac{1}{2}\:cm}}\Longleftarrow(distance)\end{array}}\qquad\checkmark$

Answer:

B.) 1/2 cm

_______________________

I Hope this helps, greetings ... Dexteright02! =)

7 0

2 years ago