The answer to this is c the chime of thunder'
Assuming that all energy of the small ball is transferred
to the bigger ball upon impact, then we can say that:
Potential Energy of the small ball = Kinetic Energy of
the bigger ball
Potential Energy = mass * gravity * height
Since the small ball start at 45 cm, then the height
covered during the swinging movement is only:
height = 50 cm – 45 cm = 5 cm = 0.05 m
Calculating for Potential Energy, PE:
PE = 2 kg * 9.8 m / s^2 * 0.05 m = 0.98 J
Therefore, maximum kinetic energy of the bigger ball is:
<span>Max KE = PE = 0.98 J</span>
If it were possible to move a star towards the earth then its apparent magnitude number would decrease while its absolute magnitude number would stay the same.
Definition of apparent magnitude:
The luminosity of a celestial body (such as a star) as observed from the earth compare absolute magnitude.
So for example, the apparent magnitude of the Sun is -26.7 and is the brightest celestial object we can see from Earth. However, if the Sun were 10 parsecs away, its apparent magnitude would be +4.7, only about as bright as Ganymede appears to us on Earth.
Definition of absolute magnitude:
Absolute magnitude is a measure of the luminosity of a celestial object on an inverse logarithmic astronomical magnitude scale.
To learn more about apparent magnitude here
brainly.com/question/2949443
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by angular momentum conservation we will have
angular momentum of child + angular momentum of merry go round = 0
angular momentum of child = mvR
m = mass of child
R = radius of child
v = speed = 2 m/s
now let's say moment of inertia of merry go round is I
so we will have


so merry go round will turn in opposite direction with above speed