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3 years ago

If you fill a glass to the brim with ice water and the ice melts, what will happen?

Chemistry

2 answers:

Natalija [7]3 years ago

7 0

Hello There!

When the ice melts, the water level will drop slightly but not much.

REMEMBER Ice expands so when ice melts, it shrinks back to the state of being liquid.

cricket20 [7]3 years ago

4 0

<h2>Answer:</h2>

No change is witnessed as the weight of the ice and water is equal.

<h2>Explanation:</h2>

At the point when an ice cube is set in a glass of water, it uproots enough water to help its weight and leads to the condition:

Weight of an ice cube = mass of water/thickness of water.

After the ice cube melts totally the water level continues as before as the water uprooted is currently satisfied by the measure of water present in the ice (3D shape). Indeed, even in the wake of liquefying, the measure of water in the ice cube will gauge is equal mass of ice block/thickness of water.

As the weight stays same, the measure of water dislodged doesn't change and the water level continues as before. But, there are some water droplets around the glass.

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1N2 + 3H2 -->

Hunter-Best [27]

Answer:

28.23 g NH₃

Explanation:

The balanced chemical equation is:

N₂(g) + 3 H₂(g) → 2 NH₃(g)

Thus, 1 mol of N₂ reacts with 2 moles of H₂ to produce 2 moles of NH₃. We convert the moles to mass (in grams) by using the molecular weight (MW) of each compound:

MW(N₂) = 2 x 14 g/mol = 28 g/mol

mass N₂= 1 mol x 28 g/mol = 28 g

MW(H₂) = 2 x 1 g/mol = 2 g/mol

mass H₂ = 3 mol x 2 g/mol = 6 g

MW(NH₃) = 14 g/mol + (3 x 1 g/mol) = 17 g/mol

mass NH₃= 2 moles x 17 g/mol = 34 g

Now, we have to figure out which is the limiting reactant. For this, we know that the stoichiometric ratio is 28 g N₂/6 g H₂. If we have 36.85 g of H₂, we need the following mass of N₂:

36.85 g H₂ x 28 g N₂/6 g H₂ = 171.97 g N₂

We have 23.15 g N₂ and we need 171.97 g. So, we have lesser N₂ than we need. Thus, the limiting reactant is N₂.

Now, we calculate the product (NH₃) by using the stoichiometric ratio 34 g NH₃/28 g N₂, with the mass of N₂ we have:

23.25 g N₂ x 34 g NH₃/28 g N₂ = 28.23 g NH₃

Therefore, the maximum amount of NH₃ that can be produced is 28.23 grams.

5 0

3 years ago

10. Sound is characterized in how many ways?<br> A. 5<br> B. 3<br> C. 4<br> D. None of the above

Elodia [21]

Answer:

A . 5...................

8 0

2 years ago

Read 2 more answers

How many sodium atoms does 2NaOH have?

attashe74 [19]

Answer:

Explanation:

5 0

3 years ago

Read 2 more answers

A gaseous mixture composed of 20% CH4, 30% C2H4, 35% C2H2, and 15% C2H20. What is the average molecular weight of the mixture? a

Semenov [28]

<u>Answer:</u> The correct answer is Option d.

<u>Explanation:</u>

We are given:

Mass percentage of $CH_4$ = 20 %

So, mole fraction of $CH_4$ = 0.2

Mass percentage of $C_2H_4$ = 30 %

So, mole fraction of $C_2H_4$ = 0.3

Mass percentage of $C_2H_2$ = 35 %

So, mole fraction of $C_2H_2$ = 0.35

Mass percentage of $C_2H_2O$ = 15 %

So, mole fraction of $C_2H_2O$ = 0.15

We know that:

Molar mass of $CH_4$ = 16 g/mol

Molar mass of $C_2H_4$ = 28 g/mol

Molar mass of $C_2H_2$ = 26 g/mol

Molar mass of $C_2H_2O$ = 48 g/mol

To calculate the average molecular mass of the mixture, we use the equation:

$\text{Average molecular weight of mixture}=\frac{_{i=1}^n\sum{\chi_im_i}}{n_i}$

where,

$\chi_i$ = mole fractions of i-th species

$m_i$ = molar masses of i-th species

$n_i$ = number of observations

Putting values in above equation:

$\text{Average molecular weight}=\frac{(\chi_{CH_4}\times M_{CH_4})+(\chi_{C_2H_4}\times M_{C_2H_4})+(\chi_{C_2H_2}\times M_{C_2H_2})+(\chi_{C_2H_2O}\times M_{C_2H_2O})}{4}$

$\text{Average molecular weight of mixture}=\frac{(0.20\times 16)+(0.30\times 28)+(0.35\times 26)+(0.15\times 42)}{4}\\\\\text{Average molecular weight of mixture}=6.75$

Hence, the correct answer is Option d.

3 0

3 years ago

Compare and contrast a pure substance with a mixture and give an example.

Inessa [10]

Of any substance? What about two powders such as 1/2 cup of white flour, then mixing 1/2 cup of salt together with the flour. This would then form a more coarse mixture being that the two particles differ in shape.

3 0

3 years ago