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azamat
3 years ago
10

How many moles of Fe2O3 will be produced from a 18.0 grams of Fe

Chemistry
2 answers:
nadya68 [22]3 years ago
7 0

Answer:

0.161 moles of Fe2O3 produced.

Explanation:

This is Khan academy's answer!

Dennis_Churaev [7]3 years ago
6 0

Answer:

The answer to your question is 0.113 moles of Fe₂O₃

Explanation:

Data

moles of Fe₂O₃ = ?

mass of Fe₂O₃ = 18 grams

Process

1.- Calculate the molar mass of Fe₂O₃

Fe₂O₃ = (56 x 2) + (16 x 3)

          = 112 + 48

          = 160 g

2.- Use proportions to solve this problem. The molar mass is equivalent to 1 mol.

                   160 g of Fe₂O₃ --------------- 1 mol

                     18 g of Fe₂O₃ ---------------- x

                            x = (18 x 1)/160

                           x = 0.113 moles of Fe₂O₃

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Question #1
Potasium hydroxide (known)
 volume used is 25 ml 
Molarity (concentration) = 0.150 M
Moles of KOH used 
           0.150 × 25/1000 = 0.00375 moles
Sulfuric acid (H2SO4) 
volume used = 15.0 ml
unknown concentration
The equation for the reaction is
2KOH (aq)+ H2SO4(aq) = K2SO4(aq) + 2H2O(l) 
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Question #2
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Volume used = 30 ml
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