Answer:
λ = 2.8 m
Explanation:
Given data:
Frequency of radio wave = 106.7 ×10⁶ Hz
Wavelength of radio wave = ?
Solution:
Formula:
Speed of wave = frequency × wavelength
speed of wave = 3×10⁸ m/s
by putting values,
3×10⁸ m/s = 106.7 ×10⁶ Hz × λ
Hz = s⁻¹
λ = 3×10⁸ m/s / 106.7 ×10⁶ Hz
λ = 3×10⁸ m/s / 106.7 ×10⁶ s⁻¹
λ = 0.028×10² m
λ = 2.8 m
Molarity=moles/litre
molarity=0.5/0.1
molarity=5.00m
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Galaxies are composed of stars, dust, and dark matter, all held together by gravity. Below we discuss galaxy formation, galactic collisions and other facts about these so-called “island universes.” The Milky Way Galaxy is organized into spiral arms of giant stars that illuminate interstellar gas and dust.
Hope that helps........ (◕‿◕✿)
Answer:
41 g
Explanation:
We have a buffer formed by a weak acid (C₆H₅COOH) and its conjugate base (C₆H₅COO⁻ coming from NaC₆H₅COO). We can find the concentration of C₆H₅COO⁻ (and therefore of NaC₆H₅COO) using the Henderson-Hasselbach equation.
pH = pKa + log [C₆H₅COO⁻]/[C₆H₅COOH]
pH - pKa = log [C₆H₅COO⁻] - log [C₆H₅COOH]
log [C₆H₅COO⁻] = pH - pKa + log [C₆H₅COOH]
log [C₆H₅COO⁻] = 3.87 - (-log 6.5 × 10⁻⁵) + log 0.40
[C₆H₅COO⁻] = [NaC₆H₅COO] = 0.19 M
We can find the mass of NaC₆H₅COO using the following expression.
M = mass NaC₆H₅COO / molar mass NaC₆H₅COO × liters of solution
mass NaC₆H₅COO = M × molar mass NaC₆H₅COO × liters of solution
mass NaC₆H₅COO = 0.19 mol/L × 144.1032 g/mol × 1.5 L
mass NaC₆H₅COO = 41 g
