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azamat
3 years ago
10

How many moles of Fe2O3 will be produced from a 18.0 grams of Fe

Chemistry
2 answers:
nadya68 [22]3 years ago
7 0

Answer:

0.161 moles of Fe2O3 produced.

Explanation:

This is Khan academy's answer!

Dennis_Churaev [7]3 years ago
6 0

Answer:

The answer to your question is 0.113 moles of Fe₂O₃

Explanation:

Data

moles of Fe₂O₃ = ?

mass of Fe₂O₃ = 18 grams

Process

1.- Calculate the molar mass of Fe₂O₃

Fe₂O₃ = (56 x 2) + (16 x 3)

          = 112 + 48

          = 160 g

2.- Use proportions to solve this problem. The molar mass is equivalent to 1 mol.

                   160 g of Fe₂O₃ --------------- 1 mol

                     18 g of Fe₂O₃ ---------------- x

                            x = (18 x 1)/160

                           x = 0.113 moles of Fe₂O₃

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What is the standard electrode potential for a galvanic cell constructed in the appropriate way from these two half-cells?
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E

θ

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=

+

2.115

l

V

Cathode

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2

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/

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Anode

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+

/

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Explanation:

Look up the reduction potential for each cell in question on a table of standard electrode potential like this one from Chemistry LibreTexts. [1]

Mg

2

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(

a

q

)

+

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l

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(

s

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−

E

θ

=

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Ni

2

+

(

a

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+

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(

s

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−

E

θ

=

−

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The standard reduction potential

E

θ

resembles the electrode's strength as an oxidizing agent and equivalently its tendency to get reduced. The reduction potential of a Platinum-Hydrogen Electrode under standard conditions (

298

l

K

,

1.00

l

kPa

) is defined as

0

l

V

for reference. [2]

A cell with a high reduction potential indicates a strong oxidizing agent- vice versa for a cell with low reduction potentials.

Two half cells connected with an external circuit and a salt bridge make a galvanic cell; the half-cell with the higher

E

θ

and thus higher likelihood to be reduced will experience reduction and act as the cathode, whereas the half-cell with a lower

E

θ

will experience oxidation and act the anode.

E

θ

(

Ni

2

+

/

Ni

)

>

E

θ

(

Mg

2

+

/

Mg

)

Therefore in this galvanic cell, the

Ni

2

+

/

Ni

half-cell will experience reduction and act as the cathode and the

Mg

2

+

/

Mg

the anode.

The standard cell potential of a galvanic cell equals the standard reduction potential of the cathode minus that of the anode. That is:

E

θ

cell

=

E

θ

(

Cathode

)

−

E

θ

(

Anode

)

E

θ

cell

=

−

0.257

−

(

−

2.372

)

E

θ

cell

=

+

2.115

Indicating that connecting the two cells will generate a potential difference of

+

2.115

l

V

across the two cells.

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2 years ago
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Answer:

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