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fgiga [73]
3 years ago
8

Effects of warm tropical waters meeting with cool air.

Chemistry
1 answer:
Mars2501 [29]3 years ago
6 0
A hurricane.. I believe
You might be interested in
How is the potential (voltage) of a redox reaction determined using the reduction
LuckyWell [14K]

Answer:

caused by the ability of electrons to flow from one half cell too the other

Explanation:

How is the potential voltage of a redox reaction?

The potential difference is caused by the ability of electrons to flow from one half cell to the other. Electrons are able to move between electrodes because the chemical reaction is a redox reaction. A redox reaction occurs when a certain substance is oxidized, while another is reduced.

6 0
2 years ago
What is hydrogen ion concentration of an acid solution whose PH is 3.4?​
meriva
It’s easy, if the PH of any acidic solution = -Log[H+], where [H+] is hydrogen ion concentration, multiply each term by (-1) then raise each term as a power to (10), so it will become like this:-
[H+] = 10^(-PH)
4 0
3 years ago
What is the [H ] of a solution of 0.001 M aqueous sulfuric acid (H2SO4) is H2SO4 ionizes in water according to the balanced chem
Ainat [17]

Answer:  0.002 M

Explanation:

The balanced chemical equation for ionization of H_2SO_4 in water is:

H_2SO_4\rightarrow 2H^++SO_4^{2-}

According to stoichiometry :

1 mole of H_2SO_4 ionizes to give =2 mole of H^+ ions

0.001 mole of H_2SO_4 ionizes to give = \frac{2}{1}\times 0.001=0.002 mole of H^+ ions

Thus H^+ of a solution of 0.001 M aqueous sulfuric acid is 0.002 M

4 0
2 years ago
I need help ASAP!!!!! What happens to water when it changes to ice?
Gre4nikov [31]

- It's density increases

- mass increases

- volume increases

Hope this helps!

6 0
3 years ago
Read 2 more answers
At a certain temperature, the solubility of strontium arsenate, sr3(aso4)2, is 0.0480 g/l. what is the ksp of this salt at this
Nadusha1986 [10]
Given the solubility of strontium arsenate is 0.0480 g/l . we have to convert it into mol/L by dividing it over molar mass (540.7 g/mol)
Molar solubility = 0.0480 / 540.7 = 8.9 x 10⁻⁵ mol/L
Dissociation equation:
Sr₃(AsO₄)₂(s) → 3 Sr²⁺(aq) + 2 AsO₄³⁻(aq)
                             3 s                   2 s
Ksp = [Sr²⁺]³ [AsO₄³⁻]²
       = (3s)³ (2s)²
       = 108 s⁵
Ksp = 108 (8.9 x 10⁻⁵) = 5.95 x 10⁻¹⁹ 
8 0
3 years ago
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