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3 years ago

A substance has a volume of 10.0 cm3 and a mass of 89 grams. What is its density?

Chemistry

2 answers:

forsale [732]3 years ago

7 0

Answer: The density of the object will be $8.9g/cm^3$

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}$

Given information:

Mass of object = 89 grams

Volume of object= $10cm^3$

Putting in the values we get:

$Density=\frac{89g}{10cm^3}=8.9g/cm^3$

Thus density of the object will be $8.9g/cm^3$

Irina18 [472]3 years ago

5 0

Remembering that
d = m ÷ v

d = ?
m = 89 g
v = 10 cm³

Therefore:

d = 89 ÷ 10

d = 8,9 g÷cm³

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2 years ago

Given the following data: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) ΔH = −23 kJ 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ΔH = −39

nalin [4]

Answer:

ΔH° = -11 kj

Explanation:

Step 1: Data given

1) Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) ΔH = −23 kJ

2) 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ΔH = −39 kJ

3) Fe3O4(s) + CO(g) → 3 FeO(s) + CO2(g) ΔH = +18 kJ

Step 2: The balanced equation

FeO + CO → Fe + CO2

Step 3: Calculate ΔH for the reaction FeO(s) + CO(g) → Fe(s) + CO2(g).

To get this equation, we need to combine the 3 equations

We have to multiply the third equation by 2.

2Fe3O4(s) + 2CO(g) → 6 FeO(s) + 2CO2(g) ΔH = +54 kJ

This equation we add to the second equation

3Fe2O3(s) + CO(g) + 2Fe3O4(s) + 2CO(g) → 2Fe3O4(s) + CO2(g) + 6FeO(s) + 2CO2 (g)

3Fe2O3(s) + 3CO(g) → 3CO2(g) + 6FeO(s)

ΔH° = 2*18 + (-39) = 36 - 39 = -3 kJ

This new equation we will divide by 3

3Fe2O3(s) + 3CO(g) → 3CO2(g) + 6FeO(s)

Fe2O3(s) + CO(g) → CO2(g) + 2FeO(s)

ΔH° =-3/3 = -1 kJ

Now we will substract this new equation from the first equation

Fe2O3(s) + 3CO(g) - Fe2O3(s) - CO(g) → 2Fe(s) + 3CO2(g) -2FeO(s) - CO2(g)

2CO(g) + 2FeO(s) → 2Fe(s) + 2CO2(g)

ΔH° = -23kJ +1kJ

ΔH° = -22 kj

The next equation we will divide by 2

2CO(g) + 2FeO(s) → 2Fe(s) + 2CO2(g)

CO(g) + FeO(s) → Fe(s) + CO2(g)

ΔH° = -22kJ /2

ΔH° = -11 kj

7 0

3 years ago

group of atoms that gains or loses electrons is called _______. A. a polar ion B. a non-polar ion C. a polyatomic ion D. a commo

raketka [301]

Answer: Option (C) is the correct answer.

Explanation:

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When a neutral atom gain an electron then it forms a negative ion whereas when a neutral atom tends to lose an electron then it forms a positive ion.

For example, a neutral fluorine atom on gaining an electron will form $F^{-}$ ion. And, a sodium atom on losing an electron forms $Na^{+}$ ion.

When a group of atoms form ions then it tends to form polyatomic ions.

Thus, we can conclude that group of atoms that gains or loses electrons is called a polyatomic ion.

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