Question

A car moves along a circular track of radius 250 ft such that its seed for a short period of time 0<_ t <_ 4s, is v = 3(t - t^2) ft/s, where t is in seconds.
a. Determine the magnitude of its acceleration when t = 3s.

b. How far has it traveled in t = 3s?

Answer 1

Answer: a) -5 ft/s²

B) 4.5 ft

Explanation: Radius= 250ft

Velocity V = 3(t-t²)ft/s

A). When t= 3 s, the acceleration is

dv/dt = 1-2t

dv/dt = 1- 2(3)

= 1-6

= -5 ft/s²

B. How far it traveled in 3 sec

Distance= 3t²/2 -t³/3 ft

Substituting 3

Distance = 27/2 - 9

= 13.5 - 9

= 4.5 ft