Answer:
The pressure increases by a factor 8
Explanation:
For a gas held at constant temperature, Boyle's law can be applied. It states that the product of the gas pressure and the gas volume is constant, so we can write:
where
is the initial pressure
is the final pressure
is the initial volume
is the final volume
For the gas in this problem, the volume is reduced from
to
so we can rewrite the equation as
this means that the pressure of the gas will increase by a factor 8.
Answer;
Q = 359.2-J
Explanation;
Given that;
Constants for mercury at 1 atm
Heat capacity of Hg(l) is 28.0 J/(mol*K)
melting point is 234.32 K
Enthalpy of fusion is 2.29 kJ/mol
17.7-g Hg / 200.6g/mol = 0.0882 mol Hg;
°C + 273 = 298 K;
2.29-kJ/mol = 2290-J/mol
Q = (m x ΔT x Cp) + (m x Hf)
Q = 0.0882-mol x (298 - 234.32) x 28.0-J/mol*K) + (0.0882-mol x 2290-J/mol)
Q = 157.26-J + 201.978-J
Q = 359.2-J
Q=359-J (3 sig fig allowed due to 17.7-g given in problem)
Answer:
Potential energy 
Explanation:
Given data
Weight of the person = 1000 N
Mass of the person = 
Speed = 6.26 
Kinetic energy is given by
Put the values in above formula we get
When the person reach top point then at this point the velocity is zero & kinetic energy at top point is equals to the potential energy.
Therefore potential energy
Answer:
dT(t)/dt = k[T5 - T(t)]
Explanation:
Since T(t) represents the temperature of the object and T5 represents the temperature of the surroundings, according to Newton's law of cooling, the rate at which an object's temperature changes is directly proportional to the difference in temperature between the object and the surrounding medium, that is dT(t)/dt ∝ T5 - T(t)
Introducing the constant of proportionality
dT(t)/dt = k[T5 - T(t)]
which is the desired differential equation
