Let U = {1,2,3,4,5,6,7,8,9,10}, A = {1,3,5,7,9}, B = {2,4,6,8,10} and C = {1,2,3,4} find (i) U' ii) A∩A' iii) A – ( B U C) iv) A
Artyom0805 [142]
Answer:
(i) U' = Φ
(ii) A∩A' = Φ
(iii) A – ( B U C) = {5,7,9}
(iv) A' U ( B U C ) = {2,4,6,8,10}
(v) A' U ( B' ∩ C') = {2,4,5,6,7,8,9,10}
Step-by-step explanation:
Answer:
an unbroken part of a circle consisting of two points on the circle called the endpoints and all the points of the circle between them. arc. an arc of a circle whose points are on or in the interior of a central angle.
You can figure this out by setting up an equation and make
x= tens digit
y= ones digit
y + 8 =x (tens digit 8 more than ones)
also we know that
y>0
x>0
since the 10s digit and 1s digit cannot be more than one number, we can say
0 < y > 10
0 < x > 10
since x has to be greater than 0 but less than 10, there is only one number that would fit into the equation for y
2 + 8 = 10
(y cannot equal 2 because than x is equal to 10 and it must be less than)
1 + 8 = 9
( y can be 1 since x is less than 10)
so it would be
y= 1
x= 9
the number would be 91
hope this helped!
Answer:
(f+g)(x) > 3 for all values of x
the 6 is the 6 x's that is in the diagram
