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deff fn [24]
3 years ago
10

Based on the location of nitrogen on the periodic table how many additional electrons does a nitrogen atom need in its valence s

hell to satisfy the oh slip rule when it comes to form bonds
Chemistry
1 answer:
igor_vitrenko [27]3 years ago
5 0
1 additional electron
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<span>Answer: Nothing is balanced in your final equation: not H, not O, not Cr, not I and your charges aren't either. Start with your 2 half reactions: I- --> IO3- Cr2O72- --> 2 Cr3+ Balance O by adding H2O: I- + 3 H2O --> IO3- Cr2O72- --> 2 Cr3+ + 7H2O Balance H by adding H+: I- + 3 H2O --> IO3- + 6 H+ Cr2O72- + 14 H+ --> 2 Cr3+ + 7H2O Balance charge by adding e-: I- + 3 H2O --> IO3- + 6 H+ + 6 e- Cr2O72- + 14 H+ + 6 e- --> 2 Cr3+ + 7H2O Since the numbers of electrons in your two half reactions are the same, just add them and simplify to give: Cr2O72- + I- + 8 H+ --> IO3- + 2 Cr3+ + 4 H2O</span>
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3 years ago
Which statements describe the Rutherford atomic model? Check all that apply.
MaRussiya [10]

Answer:

1 and 4

Explanation:

7 0
2 years ago
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Indicate the peptides that would result from cleavage by the indicated reagent: a. Gly-Lys-Leu-Ala-Cys-Arg-Ala-Phe by trypsin b.
Ilia_Sergeevich [38]

Answer:

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Explanation:

In this case, we have to remember which peptidic bonds can break each protease:

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It breaks selectively the peptidic bond in the carbonyl group of lysine or arginine.

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With this in mind in "peptide a", the peptidic bonds that would be broken are the ones in the <u>"Lis"</u> and <u>"Arg"</u> (See figure 1).

In "peptide b", the peptidic bond that would be broken is the one in the <u>"Phe"</u> (See figure 2). The second amino acid that can be broken is <u>tyrosine</u>, but this amino acid is placed in the <u>C terminal spot</u>, therefore will not be involved in the <u>hydrolysis</u>.

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3 years ago
Element A has 15 protons. Determine the number of neutrons in its isotope with mass number 33.
bagirrra123 [75]
In an electrically neuteral atom, number of protons = number of electrons = atomic number.
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Therefore,
neutrons = mass number - <span>protons/electrons/atomic number
Neutrons = 33 - 15 = 18

The answer is thus B. But this is the solution and explanation along with it as proof.</span>
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