Answer:
check the screen shot please
wavelength =wavevelocity
--——————
Frequency
Frequency = 1/T => 1 / 6.73 = 0.1486
Wave velocity = L/T => 3.75 / 6.73 = 0.5572
Therefore, wave length = 0.5572/0.1486 = 3.75m
Answer:
T_2= 234.37 K
Explanation:
According to Claperyon, we know that

P_1= Atmospheric pressure 760 mm Hg
P_2 = pressure at the bottom of the column
= 10×10^3 mm of Hg+ 760 mm of Hg
= 10760 mm of Hg
now,
P_2-P_1= 10760-760= 10^4 mm
P_2-P_1 ( in pascals) = 10^4× 133.322= 1333220 mm
the enthalpy of fusion (ΔH-fus) of mercury is 2.292 KJ/mol
use the above equation to calculate ΔT as follows

therefore, T_2= 234.37 K
Answer:
1. Momentum is conserved in the collision.
Explanation:
1. Which statement best describes this collision as compared to other types collision?
a. The colliding bodies do not stick together
b. Kinetic energy is conserved in the collision
c. Momentum is conserved in the collision. True
d. None of the statements describe the collision.
e. The colliding bodies stick together.
The questions 2, 3 and 4 are not completed.