The period of oscillation of the system is 12.56 s
Explanation:
The period of oscillation of a spring-mass system is given by

where
m is the mass attached to the spring
k is the spring constant
For the system in this problem, we have
m = 40 kg
k = 10 N/m
Substituting into the equation, we find

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Answer:
You will need 450 cells (3 cm each) to meet the voltage/current requirement.
The panel must be 3 cells in one side, by 150 cell in another side. 1350 cm^2 or 0.135 m^2. They must be connected 3 in row in parallel (to add current), then each of the former group must be connected in series to meet the voltage, so it would be 150 rows of connected in series.
The panel can be optimized using a voltage inverter, to convert current to voltage. In this way, less cells can be used achieving the same output specs.
Explanation:
To meet the voltage:
120 [v] required voltage
0.8 [v] voltage of each cell
![\frac{120}{0.8} =150[v]\\](https://tex.z-dn.net/?f=%5Cfrac%7B120%7D%7B0.8%7D%20%3D150%5Bv%5D%5C%5C)
So we need 150 cells in series for the voltage.
To meet the current
1.0 [A] Required current
350[mA]=0.35[A] cell current
1/0.35=3 cell So we need 3 cells in parallel to add the currents and meet the requirement.
See the attached figure
Then the magnitude of the net force is the difference between the two forces,
and its direction is the same as the direction of the greater one.