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jeyben [28]
3 years ago
5

In what sense can a transformer be considered an electrical lever? What does it multiply? What does it not multiply?

Physics
1 answer:
liberstina [14]3 years ago
5 0

Answer:

This is because it steps up or steps down electrical voltage. It multiplies either voltage (if it is a voltage transformer )or current (if it is a current transformer), but it does not multiply electrical power.

Explanation:

A transformer steps up or steps down electrical voltage, by transmitting power at a voltage, V₁ and Current I₁ at one terminal, to a voltage, V₂ and Current I₂ at its other terminals, just like a lever transmits force from one point to another. Since the power transmitted remains the same, (energy per unit time remains constant), I₁V₁ = I₂V₂ ⇒ I₁/I₂ = V₂/V₁ = n (the turns ratio of the transformer). So, the turns ratio will determine if its a step-up or step-down transformer. V₂ = nV₁. So, if V₁ > V₂ it is a step down transformer and if V₁ < V₂ it is a step-up transformer.It multiplies either voltage (if it is a voltage transformer )or current (if it is a current transformer), but it does not multiply electrical power, since P = IV = constant for the transformer.

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3 years ago
If earth increase the distance from the sun, what will happen to the period of orbi t(the time it takes to complete one revoluti
Mandarinka [93]

The period of the orbit would increase as well

Explanation:

We can answer this question by applying Kepler's third law, which states that:

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5 0
3 years ago
What is the difference between current and voltage besides their units of measurement
kondor19780726 [428]
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8 0
3 years ago
A team of dogs accelerates a 290kg dogsled from 0 to 6.0m/s in 3.0 s. Assume that the acceleration is constant.Part AWhat is the
Mademuasel [1]

Answer:

(a) a=2m/sec^2

(b) 5220 j

(c) 1740 watt

(d) 3446.66 watt

Explanation:

We have given mass m = 290 kg

Initial velocity u = 0 m/sec

Final velocity v = 6 m/sec

Time t = 3 sec

From first equation of motion

v = u+at

So a=\frac{v-u}{t}=\frac{6-0}{3}=2m/sec^2

(a) We know that force is given by

F = ma

So force will be F=290\times 2=580N

(b) From second equation of motion we know that

s=ut+\frac{1}{2}at^2=0\times 3+\frac{1}{2}\times 2\times 3^2=9m

We know that work done is given by

W = F s = 580×9 =5220 j

(c) Time is given as t = 3 sec

We know that power is given as

P=\frac{W}{t}=\frac{5220}{3}=1740Watt

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So P=\frac{W}{t}=\frac{5220}{1.5}=3466.66Watt

5 0
4 years ago
Find the distance in nm between two slits that produces the first minimum for 410-nm violet light at an angle of 14.5°.
Galina-37 [17]

Answer:

820 nm

Explanation:

We are given that

Wavelength=\lambda=410 nm

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1nm=10^{-9} m

\theta=14.5^{\circ}

For first minimum therefore

m=0

We know that for destructive interference

(m+\frac{1}{2})\lambda=dsin\theta

Substitute the values

(0+\frac{1}{2})\times 410\times 10^{-9}=dsin 14.5

d=\frac{410\times 10^{-9}}{2\times sin 14.5}

d=820\times 10^{-9} m=820 nm

Hence, the distance between two slits that produces the first minimum=820 nm

5 0
3 years ago
Read 2 more answers
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