2 years ago

If a triangle jkl is classified as isosceles

Mathematics

1 answer:

forsale [732]2 years ago

5 0

Yes it is isosceles

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4/5 and 3/7 plz help

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Answer:

What are you trying to ask

Step-by-step explanation:

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2 years ago

(ab^2 x -b^4a^3)^2<br><br> What is the answers

Umnica [9.8K]

Answer:

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

Step-by-step explanation:

Given the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

solving the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

$\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2$

$a=ab^2x,\:\:b=b^4a^3$

so the expression becomes

$=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2$

$=a^2b^4x^2-2a^4b^6x+a^6b^8$

Thus,

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

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2 years ago

What is the value of u ?

nataly862011 [7]

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2 years ago

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What is the nth term of the geometric sequence 4, 8, 16, 32, ... ?

Morgarella [4.7K]

Geometric is
$a_n=a_1r^{n-1}$
an=nth term
a1=first term
r=common ratio
n=which term

commmon ratio is like
a1 times r=a2
4 to 8
4 times 2=8
r=2
first term is 4
therefor

$a_n=4(2)^{n-1}$
the nth term is $4(2)^{n-1}$

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3 years ago

Does anyone know this one?

erastova [34]

The answer is C, you double 8 million and then double 16 million

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2 years ago