A 0.50 kg rubber ball has a speed of 1.90 m/s at point a and kinetic energy of 8.9 j at point
1 answer:
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Answer:
Explanation:
For rate of flow of liquid in a pipe , the formula is
Q = π p r⁴ / 8 η l
where Q is volume of liquid flowing per unit time , p is pressure drop across pipe , r is radius of pipe , η is coefficient of viscosity and l is length of pipe
If η and l are constant for two pipes having equal rate of flow as in the given case
p₁ r₁⁴ = p₂ r₂⁴
p₁ = 1.789 p₂ ( given )
r₁ = D/2
1.789 p₂ x (D/2)⁴ = p₂ x r₂⁴
r₂ =
2 x r₂ = D x 1.1565
D₂ = D x 1.1565
Answer:
The period of the resulting oscillatory motion is 0.20 s.
Explanation:
Given that,
Spring constant
We need to calculate the time period
The object is at rest and has no elastic potential but it does has gravitational potential.
If the object falls then the the gravitational potential change in to the elastic potential.
So,
Where,h = distance
k = spring constant
Put the value into the formula
Using formula of time period
Put the value into the formula
Hence, The period of the resulting oscillatory motion is 0.20 s.