1.) Power, P = V²/R = 800²/45 = 4.5 W (A).
2.) Six Resistors in Series.
R = R1 + R2 + R3 + R4 + R5 + R6, Since R is the same, R = 20
R total = 6*20 = 120 (D)
3.) It is the current. Series connection is to evaluate current. (B)
Answer:
Current needed = 704A
Explanation:
Using the fomula; torque(τ) = (I)(A)(B)Sinθ
Where B = uniform magnetic field
I = current and A = Area
Diameter = 19cm = 0.19m so, radius = 0.19/2 = 0.095m
Area(A) = πr^(2) = πr^(2)
= π(0.095)^(2) = 0.0284 m^(2)
Now, B(earth)= 5x10^-5 T
While, we can ignore the angle because it's insignificant since the angle of the wire is oriented for maximum torque in the earth's field.
Now, if we arrange the formula to solve for charge (I):
I = (τ)/(A)(B)
I = (1.0x10^-3) / (0.0284)(5x10^-5)
I = 704A
-- Gold is a more dense substance than iron. At 19.3 times the density
of water, it's in the top few most dense substances in all of nature.
The density of iron is only 7.87 ... only 40% the density of gold !
-- Density doesn't depend on how much of the substance you have.
A flake of gold foil is still more dense than an iron battleship.
Answer:
1.10^6 kg of mass per second
Explanation:
All energy lost by the sun comes from nuclear fusion.
Sun loses energy at 2.5*10^{19}J per hour, that is 9*10^{22}J/s
To find the mass lost by the sun in liberation of energy you use the famous Einstein's equation:
hence, the sun liberates 1.10^6 kg of mass per second
The three longest wavelengths for the standing waves on a 264-cm long string that is fixed at both ends are:
- 5.2 meters.
- 2.6 meters.
- 1.7meters.
Given data:
Length of the fixed string = 264cms = 2.64 meters
The wavelength for standing waves is given by:
λ = 2L/n
where,
- λ is the wavelength
- L is the length of the string
For n = 1,
= 5.2 meters
For n = 2,
= 2.6 meters
For n = 3,
= 1.7 meters
To learn more about standing waves: brainly.com/question/14151246
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