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3 years ago

15

In a series circuit, there are 12 light bulbs, each providing 1 ohm of resistance. What is the total resistance? Group of answer

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1 answer:

belka [17]3 years ago

3 0

Answer:

12 Ohms

if all resistor are the same, use resistance=resistor * # of resistors.

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Explanation:

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Explanation:

It is given that,

Inductance, $L=40\ mH=40\times 10^{-3}\ H$

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Frequency, f = 60 Hz

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The current flowing through the inductor is given by :

$I_t=\dfrac{V_o}{X_L}\ (sin\ \omega t-\dfrac{\pi}{2})$

$I_t=\dfrac{\sqrt{2} V_{rms}}{X_L}\ (sin\ \omega t-\dfrac{\pi}{2})$

$I_t=\dfrac{120\sqrt{2}}{2\pi f L}\ sin(2\pi f t-\dfrac{\pi}{2})$

$I_t=\dfrac{120\sqrt{2}}{2\pi\times 60\times 40\times 10^{-3}}\ sin(2\pi \times 60\times \dfrac{1}{185})-\dfrac{\pi}{2})$

$I_t=\dfrac{120\sqrt2}{15.07}\ sin(2\pi \times 60\times \dfrac{1}{185}-\dfrac{\pi}{2})$

I = 0.091 A

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