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Radda [10]
4 years ago
15

In a series circuit, there are 12 light bulbs, each providing 1 ohm of resistance. What is the total resistance? Group of answer

choices
Physics
1 answer:
belka [17]4 years ago
3 0

Answer:

12 Ohms

if all resistor are the same, use resistance=resistor * # of resistors.

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What is the total power in a circuit if the resistance is 800 and the voltage is 60 VDC?
Darya [45]
1.)    Power, P  =  V²/R  =  800²/45 =  4.5 W  (A).

2.)  Six Resistors in Series.
R = R1 + R2 + R3 + R4 + R5 + R6,    Since R is the same, R = 20

R total = 6*20 = 120 (D)

3.)  It is the current.  Series connection is to evaluate current.  (B)
3 0
3 years ago
Read 2 more answers
People have proposed driving motors with the earth's magnetic field. This is possible in principle, but the small field means th
Whitepunk [10]

Answer:

Current needed = 704A

Explanation:

Using the fomula; torque(τ) = (I)(A)(B)Sinθ

Where B = uniform magnetic field

I = current and A = Area

Diameter = 19cm = 0.19m so, radius = 0.19/2 = 0.095m

Area(A) = πr^(2) = πr^(2)

= π(0.095)^(2) = 0.0284 m^(2)

Now, B(earth)= 5x10^-5 T

While, we can ignore the angle because it's insignificant since the angle of the wire is oriented for maximum torque in the earth's field.

Now, if we arrange the formula to solve for charge (I):

I = (τ)/(A)(B)

I = (1.0x10^-3) / (0.0284)(5x10^-5)

I = 704A

6 0
3 years ago
Why is a block of gold more dense than a block of iron of equal size ?
weeeeeb [17]

-- Gold is a more dense substance than iron.  At 19.3 times the density
of water, it's in the top few most dense substances in all of nature.
The density of iron is only 7.87 ... only 40% the density of gold !

-- Density doesn't depend on how much of the substance you have.
A flake of gold foil is still more dense than an iron battleship.

6 0
4 years ago
How much mass does the sun lose through nuclear fusion per second?
Mekhanik [1.2K]

Answer:

1.10^6 kg of mass per second

Explanation:

All energy lost by the sun comes from nuclear fusion.

Sun loses energy at 2.5*10^{19}J per hour, that is 9*10^{22}J/s

To find the mass lost by the sun in liberation of energy you use the famous Einstein's equation:

E=mc^2\\\\m=\frac{E}{c^2}=\frac{9*10^{22}}{(3*10^{8}m/s)^2}=1*10^6kg

hence, the sun liberates 1.10^6 kg of mass per second

3 0
4 years ago
What are the three longest wavelengths for standing waves on a 264- cm -long string that is fixed at both ends
miv72 [106K]

The three longest wavelengths for the standing waves on a 264-cm long string that is fixed at both ends are:

  1. 5.2 meters.
  2. 2.6 meters.
  3. 1.7meters.

Given data:

Length of the fixed string = 264cms = 2.64 meters

The wavelength for standing waves is given by:

λ = 2L/n

where,

  • λ is the wavelength
  • L is the length of the string

For n = 1,

  • λ = 2×2.6/1

= 5.2 meters

For n = 2,

  • λ = 2×2.6/2

= 2.6 meters

For n = 3,

  • λ = 2×2.6/3

= 1.7 meters

To learn more about standing waves: brainly.com/question/14151246

#SPJ4

7 0
2 years ago
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