You shine a laser beam through a grating with a known number of slits per millimeter and observe a pattern on a screen. Then you
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If gravitational effects from other objects are negligible, the speed of the rock at a very great distance from the planet will approach a value of
<u>Explanation:</u>
To express velocity which is too far from the planet and escape velocity by using the energy conservation, we get
Rock’s initial velocity
, . Here the radius is R, so find the escape velocity as follows,
Where, M = Planet’s mass and G = constant.
From given conditions,
Surface potential energy can be expressed as,
R tend to infinity when far away from the planet, so
Then, kinetic energy at initial would be,
Similarly, kinetic energy at final would be,
Here,
Now, adding potential and kinetic energies of initial and final and equating as below, find the final velocity as
'm' and as common on both sides, so gets cancelled, we get as
We know, , it can be wriiten as
, we get
Taking squares out, we get,
Answer:
Explanation:
velocity of ship with respect to water = 6.5 m/s due north
velocity of water with respect to earth = 1.5 m/s at 40° north of east
velocity of ship with respect to water = velocity of ship with respect to earth - velocity of water with respect to earth
The magnitude of the velocity of ship relative to earth is = 5.66 m/s