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marshall27 [118]
3 years ago
8

We push a 38.4-kg box across the floor at constant velocity. If we are pushing a horizontal force of 238 N, find the coefficient

of kinetic friction between the box and the floor.
Physics
1 answer:
zmey [24]3 years ago
5 0

Answer: 0.62

Explanation:

Coefficient of friction is defined as the ratio of the moving force (Fm) acting on a body to the normal reaction (R).

Note that the normal reaction acts vertically on the object and is equal to the objects weight (W) i.e W=R

Since W = mg, W = 38.4 ×10

W= 384N =R

Normal reaction = 384N

The horizontal force acting on the body will be the moving force which is 238N

Coefficient of friction = Fm/R

Coefficient of friction = 238/384

Coefficient of friction = 0.62

Therefore, coefficient of kinetic friction between the box and the floor is 0.62

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Answer:

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V_3=\frac{30}{175} *\,25=\frac{30}{7} \approx 4.28\,\,V

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10 V -  4.28 V = 5.72 V

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I_1=\frac{V_1}{R_1} =\frac{5.72}{100} =0.0572\,\,amps

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