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Sedbober [7]
3 years ago
12

What is the speed of an arrow that takes 1.25 seconds to hit a target 75 meters away?

Physics
2 answers:
coldgirl [10]3 years ago
7 0

Answer

60

Explanation:

This is because if the question gives you the distance and the time, you have to find the speed.

dimulka [17.4K]3 years ago
5 0

Answer:

60m/s

Explanation:

v=s÷t

75m÷1.25s=60m/s

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Ndividuals living in highly populated areas are more inclined to _______.
V125BC [204]

Answer:

B. Social Interaction.

Explanation:

6 0
3 years ago
The period for which an organism lives is called its _______
zepelin [54]

Answer:

c) lifespan

Explanation:

hope it's helpful for you ☺️

7 0
3 years ago
Read 2 more answers
A thin film of soap with n = 1.34 hanging in the air reflects dominantly red light with λ = 642 nm. What is the minimum thicknes
wariber [46]

Answer:

The minimum thickness of the film and the wavelength of the light in air are 1.197\times10^{-7}\ m and 371 nm.

Explanation:

Given that,

Refractive index of soap= 1.34

Refractive index  of glass= 1.55

Wavelength = 642 nm

(I). We need to calculate the minimum thickness

Using formula of thickness

t=\dfrac{(2m+1)\lambda}{4n}

Where, m = 0 for constrictive

Put the value into the formula

t=\dfrac{(642\times10^{-9})}{4\times1.34}

t=1.197\times10^{-7}\ m

(II). We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{2nt}{m}

Where, m = 1

Put the value into the formula

\lambda=\dfrac{2\times1.55\times1.197\times10^{-7}}{1}

\lambda=371\ nm

Hence, The minimum thickness of the film and the wavelength of the light in air are 1.197\times10^{-7}\ m and 371 nm.

6 0
3 years ago
Why is the answer C?
4vir4ik [10]

Explanation:

We want to find the statement that is proven by the fact that the balls reach the same height.

A isn't supported by the evidence.  Balls can reach the same height without having the same initial speed.

B isn't supported by the evidence.  Balls can reach the same height without having the same launch angle.

C is supported.  Projectiles spend the same amount of time going up as they do coming down, so if two projectiles reach the same height, then they must spend the same amount of time in the air.

D isn't supported by the evidence.  Balls thrown at the same speed and complementary angles have the same range but different heights.

E isn't supported by the evidence.  The mass of the ball doesn't affect the height.

7 0
3 years ago
(a) Neil A. Armstrong was the first person to walk on the moon. The distance between the earth and the moon is 3.85 x 108 m. Fin
gizmo_the_mogwai [7]

Answer:

a). 1.28333 seconds

b). 186.66 seconds

Explanation:

a). Given :

Distance between the earth and the moon, d = $3.85 \times 10^8$ m

Speed of the radio waves, c = $3 \times 10^8$ m/s

Therefore the time required for the voice of Neil Armstrong to reach the earth via radio waves is given by :

$t=\frac{d}{c}$

 $=\frac{3.85 \times 10^8}{3 \times 10^8}$

 = 1.28333 seconds

b). Distance between Mars and the earth, d = $5.6 \times 10^{10}$ m

   Speed of the radio waves, c = $3 \times 10^8$ m/s

So, the time required for his voice to reach earth is :

$t=\frac{d}{c}$

 $=\frac{5.6 \times 10^{10}}{3 \times 10^8}$

 = 186.66 seconds

6 0
3 years ago
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