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LuckyWell [14K]
3 years ago
9

(a) Neil A. Armstrong was the first person to walk on the moon. The distance between the earth and the moon is 3.85 x 108 m. Fin

d the time it took for his voice to reach earth via radio waves. (b) Someday a person will walk on Mars, which is 5.6 x 1010 m from earth at the point of closest approach. Determine the minimum time that will be required for that person's voice to reach earth.
Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0

Answer:

a). 1.28333 seconds

b). 186.66 seconds

Explanation:

a). Given :

Distance between the earth and the moon, d = $3.85 \times 10^8$ m

Speed of the radio waves, c = $3 \times 10^8$ m/s

Therefore the time required for the voice of Neil Armstrong to reach the earth via radio waves is given by :

$t=\frac{d}{c}$

 $=\frac{3.85 \times 10^8}{3 \times 10^8}$

 = 1.28333 seconds

b). Distance between Mars and the earth, d = $5.6 \times 10^{10}$ m

   Speed of the radio waves, c = $3 \times 10^8$ m/s

So, the time required for his voice to reach earth is :

$t=\frac{d}{c}$

 $=\frac{5.6 \times 10^{10}}{3 \times 10^8}$

 = 186.66 seconds

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The tangential acceleration instead is given by

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Since the girl is near the outer edge and the boy is closer to the centre, the value of r for the girl is larger than for the boy, so the girl has greater tangential acceleration.

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Explanation:

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3 years ago
Read 2 more answers
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belka [17]

Answer:

Data:-vi=om/s (b/c as in question penny is dropped from building means before coming to ground its initial state or velocity was considered as zero ) now distance or height h=380m and now we have to find the final velocity vf=? and the time t=?

Explanation:

So applying second eq of motion s=vit+1/2×gt² (here we have taken a gravity b/c when ever body is in vertical position then acceleration due to gravity is applied ) s=0×t+1/2×gt² , s=0+1/2×9.8×t² ,380=4.9t² we have to find t so 4.9t²=380 , t²=380÷4.9 , t²=77.55 now sq root on b/s

\sqrt{t }  =  \sqrt{77.55}

so t=8.806s and now apply 1st eq o²f motion to find out vf so vf=vi+gt , vf=0+9.8×8.806 ,vf=86.298 and if you want to verify that either this is answer is correct or not so put the value of t in second eq of motion and if you got distance same as give in the question so your value of t is considered as correct likewise s=vit+1/2gt² , s=0+1/2×9.8(8.806)²,s=4.9×77.55 ,s=380m (proved) I hope it would be helpfull

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3 years ago
Two identical cylinders at the same pressure contain the same gas. if cylinder a contains three times as much gas as cylinder b,
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By ideal gas theory, cylinder b has the higher temperature.

We need to know about the ideal gas theory to solve this problem. The ideal gas can be represented by

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The cylinder a temperature is 3 times smaller than the temperature in cylinder b.

Find more on ideal gas at: brainly.com/question/25290815

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