Answer:
The girl has greater tangential acceleration
Explanation:
The angular acceleration (
) of the merry go round is equal to the rate of the change of the angular velocity,
:

Since all the points of the merry go round complete 1 circle in the same time, the angular velocity of each point of the merry go round is the same, and so all the points also have the same angular acceleration.
The tangential acceleration instead is given by

where
is the angular acceleration
r is the distance from the centre of the merry go round
Since the girl is near the outer edge and the boy is closer to the centre, the value of r for the girl is larger than for the boy, so the girl has greater tangential acceleration.
Answer:
Neatly wrap the wire around the nail
Explanation:
hope this helps ( not sure tho )
Answer:
Data:-vi=om/s (b/c as in question penny is dropped from building means before coming to ground its initial state or velocity was considered as zero ) now distance or height h=380m and now we have to find the final velocity vf=? and the time t=?
Explanation:
So applying second eq of motion s=vit+1/2×gt² (here we have taken a gravity b/c when ever body is in vertical position then acceleration due to gravity is applied ) s=0×t+1/2×gt² , s=0+1/2×9.8×t² ,380=4.9t² we have to find t so 4.9t²=380 , t²=380÷4.9 , t²=77.55 now sq root on b/s

so t=8.806s and now apply 1st eq o²f motion to find out vf so vf=vi+gt , vf=0+9.8×8.806 ,vf=86.298 and if you want to verify that either this is answer is correct or not so put the value of t in second eq of motion and if you got distance same as give in the question so your value of t is considered as correct likewise s=vit+1/2gt² , s=0+1/2×9.8(8.806)²,s=4.9×77.55 ,s=380m (proved) I hope it would be helpfull
By ideal gas theory, cylinder b has the higher temperature.
We need to know about the ideal gas theory to solve this problem. The ideal gas can be represented by
P . V = n . R . T
where P is the pressure, V is volume, n is the number of molecules, R is the ideal gas constant and T is temperature.
From the question above, we know that
Pa = Pb = P
na = 3nb
Find the temperature of the cylinder a
P . V = n . R . Ta
Ta = P . V /( na . R )
Substitute na
Ta = P . V /( (3nb) . R )
Ta = (1/3) x (P . V /( (nb . R ))
Find the temperature of the cylinder b
P . V = n . R . Tb
Tb = P . V /( nb . R )
The cylinder a temperature is 3 times smaller than the temperature in cylinder b.
Find more on ideal gas at: brainly.com/question/25290815
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