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SVEN [57.7K]
3 years ago
8

A 2 kilogram mass is lifted 4 meters above the ground what is the change it gravitational energy

Physics
1 answer:
lianna [129]3 years ago
6 0

Answer:

78.4 J

Explanation:

The gravitational potential energy of an object is the energy possessed by the object due to its location in the gravitational field.

The change in gravitational potential energy of an object is given by:

\Delta U=mg\Delta h

where:

m is the mass of the object

g=9.8 m/s^2 is the acceleration due to gravity

\Delta h is the change in height of the object

For the mass in  this problem, we have:

m = 2 kg is the mass

\Delta h = 4 m is the change in height

So, its change in gravitational energy is:

\Delta U=(2)(9.8)(4)=78.4 J

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The speed of a wave or a pulse depends upon the properties of the medium. If the medium is uniform or unchanging, then the speed is constant. Useful Web Links. The Speed of a Wave.

7 0
3 years ago
Read 2 more answers
A uniform, solid, 1800.0 kgkg sphere has a radius of 5.00 mm. Find the gravitational force this sphere exerts on a 2.30 kgkg poi
iVinArrow [24]

Answer

given,

Mass of the solid sphere = 1800 Kg

radius of the sphere,R = 5 m

mass of the small sphere, m = 2.30 Kg

when the Point is outside the sphere the Force between them is equal to

      F = \dfrac{GMm}{r^2}   when r>R

When Point is inside the Sphere

      F = \dfrac{GMm}{R^2}\ \dfrac{r}{R}  when r<R

where r is the distance where the point mass is placed form the center

Now Force calculation

a) r = 5.05 m

       F = \dfrac{GMm}{r^2}[/tex]

       F = \dfrac{6.67\times 10^{-11}\times 1800\times 2.3}{5.05^2}

               F = 1.082 x 10⁻⁸ N

b) r = 2.65 m

      F = \dfrac{GMm}{R^2}\ \dfrac{r}{R}

      F = \dfrac{6.67\times 10^{-11}\times 1800\times 2.3}{5.05^2}\ \dfrac{2.65}{5.05}

     F = 5.68\times 10^{-9}\ N

3 0
3 years ago
An object with mass 3M is launched straight up. When it reaches its maximum height, a small explosion breaks the object into two
german

Answer:

x_{L} = 106\,m

Explanation:

Each piece is analyzed by using the Principle of Momentum Conservation and the Impulse Theorem:

Heavier object:

(2\cdot M)\cdot (0) + F\cdot \Delta t = (2\cdot M)\cdot v_{H}

Lighter object:

M\cdot (0) + F\cdot \Delta t = M\cdot v_{L}

After the some algebraic handling, the following relationship is found:

M\cdot v_{L} = 2\cdot M\cdot v_{H}

v_{L} = 2\cdot v_{H}

Given that both pieces have horizontal velocities only and both are modelled as projectiles, the horizontal component of velocity remains constant and directly proportional to travelled distance. Then:

\frac{v_{L}}{v_{H}} = \frac{x_{L}}{53\,m}

2 = \frac{x_{L}}{53\,m}

x_{L} = 106\,m

8 0
3 years ago
Two speakers are 3.0 m apart and play identical tones of frequency 170 Hz. Sam stands directly in front of one speaker at a dist
Black_prince [1.1K]

Answer:

he phase difference is π the destructive interference and the lujar is a still or silent place

Explanation:

This is a sound interference exercise where the amino difference is equal to the phase difference of the sound.

      Δr / λ = ΔФ / 2π

Let's find the path difference

     r₁ = 4m

     r₂ = √ (4² + 3²) = 5 m

     Δr = r₂ - r₁

     Δr = 5-4 = 1m

Let's find the wavelength of the sound

        v =  λ f

         λ = v / f

         λ = 340/170

         λ = 2m

Let's find the phase difference between the two waves

      ΔФ = Δr 2π / λ

      ΔФ = 1 2π / 2

      ΔФ = π

 

Since the phase difference is π the destructive interference and the lujar is a still or silent place

4 0
3 years ago
You must exert a force of 5N on a book to slide it across a table.If you do 2.5 J of work in the process, how far has the book m
I am Lyosha [343]

Answer:

0.5 m.

Explanation:

From the question given above, the following data were obtained:

Force (F) = 5 N

Work done (W) = 2.5 J

Distance (s) =?

Workdone is simply defined as the product of force (F) and distance (s) moved in the direction of the force. Mathematically, it is expressed as:

Work done (W) = Force (F) × Distance (s)

W = F × s

With the above formula, we can obtain the distance to which the book has moved as follow:

Force (F) = 5 N

Work done (W) = 2.5 J

Distance (s) =?

W = F × s

2.5 = 5 × s

Divide both side by 5

s = 2.5/5

s = 0.5 m

Therefore, the book moved 0.5 m when the force was applied.

3 0
4 years ago
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