1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lianna [129]
3 years ago
8

Which statement about ammeters and voltmeters is true? A. Current and voltage are the same throughout a circuit so where you pla

ce the ammeter and voltmeter doesn't matter. B. It doesn't matter where you place the voltmeter in a circuit, but it does matter where you place the ammeter because current can be different in different parts of a circuit. C. It doesn't matter where you place the ammeter in a circuit, but it does matter where you place the voltmeter because voltage can be different in different parts of a circuit. D. Current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmeter.
Physics
2 answers:
omeli [17]3 years ago
7 0

Answer:

D Current and voltage can be different in different parts of a circuit so it matters where you put the ammeters and the voltmeter.

Explanation:

Firstly this is the PLATO answer also have a nice day:)

Viefleur [7K]3 years ago
6 0

Answer:B

Explanation:

You might be interested in
the specific heat of water is 4.2 j/c. if it takes 31,500 joules to heat to warm 750 g of water, what was the temperature change
defon
The amount of heat needed to increase the temperature of a substance by \Delta T is given by
Q=mC_s \Delta T
where
m is the mass of the substance
C_s the specific heat capacity
\Delta T the increase in temperature

In our problem, the mass of the water is m=750 g, the specific heat is C_s = 4.2 J/g ^{\circ}C and the amount of heat supplied is Q=31500 J, so if we re-arrange the previous formula we find the increase in temperature of the water:
\Delta T= \frac{Q}{m C_s}= \frac{31500 J}{(750 g)(4.20 J/g^{\circ} C)}=10^{\circ}C
7 0
3 years ago
Suppose that a balloon is being filled with air at a rate of 10 cm3/s. (Assume that theballoon is a perfect sphere.) At what rat
Basile [38]

Answer:

Therefore the surface area of the balloon is increased at 4 cm³/s.

Explanation:

The balloon is being filled with air at a rate of 10 cm³/s

It means the volume of the balloon is increased at a rate 10 cm³/s.

i.e \frac{dv}{dt} =10 cm^3/s

Consider r be the radius of the balloon.

The volume of of a sphere is

v=\frac{4}{3} \pi r^3

Differentiate with respect to t

\frac{dv}{dt} =\frac{4}{3} \pi \times 3r^2\frac{dr}{dt}

\Rightarrow 10 =4\pi r^2\frac{dr}{dt}

\Rightarrow \frac{dr}{dt}=\frac{10}{4\pi r^2}

The surface of area of the balloon is(S) = 4\pi r^2

S=4\pi r^2

Differentiate with respect to t

\frac{dS}{dt} =4\pi\times2r\frac{dr}{dt}

\Rightarrow \frac{dS}{dt} =8\pi r\frac{dr}{dt}

Putting the value of \frac{dr}{dt}

\Rightarrow \frac{dS}{dt} =8\pi r\times\frac{10}{4\pi r^2}

\Rightarrow \frac{dS}{dt} =\frac{20}{ r}

Given that r = 5 cm

[\frac{dS}{dt}]_{r=5} =\frac{20}{ 5}  =4 cm³/s

Therefore the surface area of the balloon is increased at 4 cm³/s.

5 0
3 years ago
An elevator is moving down with an acceleration of 3.36 m/s2.
sergeinik [125]

Answer : 413.44N

Here it is given that an elevator is moving down with an acceleration of 3.36 m/s² . And we are interested in finding out the apparent weight of a 64.2 kg man . For the diagram refer to the attachment .

  • From the elevator's frame ( non inertial frame of reference) , we would have to think of a pseudo force.
  • The direction of this force is opposite to the direction of acceleration the frame and its magnitude is equal to the product of mass of the concerned body with the acceleration of the frame .
  • When a elevator accelerates down , the weight recorded is less than the actual weight .

From the Free body diagram ,

\sf\longrightarrow Weight = mg - ma \\

\sf\longrightarrow Weight = m ( g - a ) \\

  • Mass of the man = 64.2 kg

\sf\longrightarrow Weight = 64.2( 9.8 - 3.36) N\\

\sf\longrightarrow Weight = 64.2 * 6.44 N\\

\sf\longrightarrow \underline{\boxed{\bf Weight_{apparent}= 413.44 N }} \\

5 0
2 years ago
The breaking car had 10,000 J of kinetic energy before breaking after breaking it had 2000 J of kinetic energy. How much thermal
WINSTONCH [101]

Answer:

8000J

Explanation:

The kinetic energy of the car lost during breaking are converted to thermal energy and are gained by the brakes.

Kinetic energy loss by car = thermal energy gained by brakes.

∆K.E = ∆T.E ....1

The Kinetic energy loss by car can be expressed as;

∆K.E = K.E1 - K.E2

Initial K.E = K.E1 = 10000J

Final K.E = K.E2 = 2000J

∆K.E= 10000J - 2000J = 8000J

From equation 1,

∆K.E = ∆T.E

∆T.E = 8,000J

thermal energy gain by brakes = 8,000J

8 0
3 years ago
How is speed calculated? multiply velocity by displacement divide velocity by displacement multiply distance by time divide dist
maria [59]

Answer:

\huge\boxed{Divide\ distance \ by \ time}

Explanation:

Speed = Distance / Time

So, to find distance, we actually divide distance by rime.

5 0
4 years ago
Read 2 more answers
Other questions:
  • Find average speed when time= 27s and total distance is 94m
    9·1 answer
  • What carries electrons from the power supply to a load?
    5·1 answer
  • What dictates the minimum and maximum pressure allowed for plumbing fixtures?
    6·2 answers
  • Which of the following is an element?
    10·1 answer
  • Why is it incorrect to say heavy objects sink in water?
    11·1 answer
  • Help me slove this problem 115 divided by 2
    14·2 answers
  • PLEASE HELP!!!!!!! A student is trying to demonstrate static electricity, so they rub two identical balloons with a neutral rabb
    11·1 answer
  • ANOTHER PHYSICS QUESTION PLEASE HELP!
    10·1 answer
  • Rafiq has heard that continued exposure to light for 10 days can change the colour of some blue dyes used to colour cotton cloth
    10·1 answer
  • A plane is flying to Minnesota with a velocity of 277.73 km/h, N. The plane
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!