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alexira [117]
3 years ago
7

When you used the energy in our body to pull the rubber band, it was transformed into elastic potential energy. We know that ene

rgy is not created or destroyed, but 100% of the elastic potential energy was not turned into mechanical energy of the rocket. Explain what you think happened to the rest of the elastic potential energy
Physics
1 answer:
GuDViN [60]3 years ago
3 0

Answer:

Converted to heat energy

Explanation:

Some of the elastic potential energy is transformed into heat energy. When we stretch a rubber band, it is often observed that the rubber becomes warmer after the stretch and even during the stretch.

Some energy in the band initially at rest will be converted into elastic potential energy and heat energy as it is stretched .

  • The heat energy is not usually accounted for since the major concern most times is the elastic energy.
  • In this process, heat energy becomes a waste energy.
  • By deducing the efficiency, we would find that this transformation is not efficient as predicted by one of the laws of thermodynamics.

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a content creator because if i was a rapper i probably wouldn't make good songs lol

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Which of these is a unit of heat? <br> a. joule <br> b. degree celsius <br> c. kelvin <br> d. tesla
attashe74 [19]

-- Heat is a form of energy.
-- Joule is the SI unit of energy.
ergo
-- Joule is a unit of heat.

'Degree Celsius' and 'Kelvin' are units of temperature.
Heat and temperature are different things.
We won't go there right now.
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Definition: This law states that, in any process, energy is neither created nor destroyed. It can only be
Alika [10]
law of conservation of energy

aka the first law of thermodynamics
5 0
3 years ago
A rock is projected upward from the surface of the moon, at time t = 0.0 s, w a velocity of 30 m/s. The acceleration due to grav
Vinvika [58]
<h2>Answer: 277.777 m</h2>

Explanation:

The situation described here is parabolic movement. However, as we are told that the rock was<u> projected upward from the surface</u>, we will only use the equations related to the Y axis.

In this sense, the movement equations in the Y axis are:

y-y_{o}=V_{o}.t+\frac{1}{2}g.t^{2}    (1)

V=V_{o}-g.t    (2)

Where:

y  is the rock's final position

y_{o}=0  is the rock's initial position

V_{o}=30\frac{m}{s} is the rock's initial velocity

V is the final velocity

t is the time the parabolic movement lasts

g=1.62\frac{m}{s^{2}}  is the acceleration due to gravity at the surface of the moon

As we know y_{o}=0 , equation (2) is rewritten as:

y=V_{o}.t+\frac{1}{2}g.t^{2}    (3)

On the other hand, the maximum height  is accomplished when V=0:

V=V_{o}-g.t=0    (4)

V_{o}-g.t=0    

V_{o}=g.t    (5)

Finding t:

t=\frac{V_{o}}{g}    (6)

Substituting (6) in (3):

y=V_{o}(\frac{V_{o}}{g})+\frac{1}{2}g(\frac{V_{o}}{g})^{2}    (7)

y_{max}=\frac{{V_{o}}^{2}}{2g}    (8)  Now we can calculate the maximum height of the rock

y_{max}=\frac{{(30m/s)}^{2}}{(2)(1.62m/s^{2})}   (9)

Finally:

y_{max}=277.777m  

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3 years ago
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Time required for what?
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