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alexira [117]
3 years ago
7

When you used the energy in our body to pull the rubber band, it was transformed into elastic potential energy. We know that ene

rgy is not created or destroyed, but 100% of the elastic potential energy was not turned into mechanical energy of the rocket. Explain what you think happened to the rest of the elastic potential energy
Physics
1 answer:
GuDViN [60]3 years ago
3 0

Answer:

Converted to heat energy

Explanation:

Some of the elastic potential energy is transformed into heat energy. When we stretch a rubber band, it is often observed that the rubber becomes warmer after the stretch and even during the stretch.

Some energy in the band initially at rest will be converted into elastic potential energy and heat energy as it is stretched .

  • The heat energy is not usually accounted for since the major concern most times is the elastic energy.
  • In this process, heat energy becomes a waste energy.
  • By deducing the efficiency, we would find that this transformation is not efficient as predicted by one of the laws of thermodynamics.

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Answer:

The answer would be A. - the temperature remains constant

Explanation:

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How to convert acceleration to velocity.
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3 years ago
Suppose that the space shuttle Columbia accelerates at 14.0 m/s2 for 8.50 minutes after takeoff.
givi [52]

Answer:

A. speed = 7.14 Km/s

B. distance = 1820.7 Km

Explanation:

Given that: a = 14.0 m/s^{2}, t = 8.50 minutes.

But,

t = 8.50 = 8.50 x 60

  = 510 seconds

A. By applying the first equation of motion, the speed of the shuttle at the end of 8.50 minutes can be determined by;

v = u + at

where: v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.

u = 0

So that,

v = 14 x 510

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The speed of the shuttle at the end of 8.50 minute is 7.14 Km/s.

B. the distance traveled can be determined by applying second equation of motion.

s = ut + \frac{1}{2}at^{2}

where: s is the distance, u is the initial velocity, a is the acceleration and t is the time.

u = 0

s = \frac{1}{2}at^{2}

  = \frac{1}{2} x 14 x (510)^{2}

 = 7 x 260100

 = 1820700 m

The distance that the shuttle has traveled during the given time is  1820.7 Km.

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