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djyliett [7]
3 years ago
8

Which statement describes a surface wave?

Physics
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer: A surface wave is a wave that moves along the interface of two different materials, like air and water.

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PLEASE HELP ME WITH THIS ONE QUESTION
Oliga [24]

OPTION D is the correct answer.

Refer to the attachment for complete calculation...

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Why should you explore the potential roadblocks to your chosen career?
valina [46]

Answer: D

Explanation: D is the most reasonable answer because it's always good to plan ahead for anything, so if you were to plan ahead for future obstacles, then you can overcome them.

6 0
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PLZ HELP
TEA [102]

Answer:

The ion has more protons than electrons.

Explanation:

6 0
3 years ago
John is a runner.He runs the 100m sprint in 10.6s.What speed did he travel at (in m/s)​
astraxan [27]
ANSWER: 9.4ms a second

EXPLANATION

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5 0
3 years ago
Read 2 more answers
You have 2 resistors of unknown values you label Ra and Rb. You have an old battery and a multimeter you bought years ago for 7$
Veseljchak [2.6K]

Answer:

the answers, the correct one is D,   Rb₂ = 29.97 ohm

Explanation:

For this exercise we use ohm's law and the equivalent resistance ratio for series and parallel circuits.

Serial circuit

         (Ra + Rb) is = V

         (Ra + Rb) 0.111 = 10

         (Ra + Rb) = 10 / 0.111 = 90.09

parallel circuit

         \frac{1}{R} = \frac{1}{Ra} + \frac{1}{Rb}

           R = \frac{Ra \ Rb}{Ra + Rb}

          \frac{Ra \ Rb}{Ra + Rb} i_p = V

         \frac{Ra \ Rb}{Ra + Rb} 0.5 = 10

         \frac{Ra \ Rb}{Ra + Rb} = 10 / 0.5 = 20

we write and solve our system of equations

         Ra + Rb = 90.09

         \frac{Ra \ Rb}{Ra + Rb} = 20

         

we solve for Ra in the first equation

          Ra = 90.09 - Rb

           RaRb = 20 (Ra + Rb)

we substitute Ra in the second equation

           (90.09-Rb) Rb = 20 [(90.09-Rb) + Rb]

            90.09 Rb - Rb² = 20 90.09

           

            Rb² - 90.09 Rb + 1801.8 = 0

we solve the quadratic equation

            Rb = [90.09 ±\sqrt{90.09^2 - 4 \ 1801.8} ] / 2

            Rb = [90.09 ± 30.15] / 2

            Rb₁ = 60.12 ohm

            Rb₂ = 29.97 ohm

the smallest value is Rb = 30 ohm

When checking the answers, the correct one is D

6 0
3 years ago
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