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Andrei [34K]
3 years ago
8

What is the difference between inner and outter goals? Can I also get an example of each?

Mathematics
1 answer:
love history [14]3 years ago
4 0
The outer is defined as the focus being on becoming someone or achieving something. The focus of the inner is being at peace with oneself.
the outer is the desire for success, recognition, power, money, knowledge, respect, etc.
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1) 5(h + 9) = 55 Distribute _____ to everything in parentheses.
NikAS [45]
9 + h = 55/5
9 + h = 11
11 - 9 = h
2 = h

The opposite of addition is subtraction, Subtract 9 from both sides, The opposite of multiplication is division, divide both sides by 5 is the first step, and final answer is h = 2.
8 0
3 years ago
$12,800 15% is taken out what's the answer
Anuta_ua [19.1K]

Answer:

$10,880

Step-by-step explanation:

15% = 15 ÷ 100 = 0.15

So 15% of 12800 = 0.15 x 12800 = 1920

Therefore, 12800 - 1920 = 10880

OR

12800 x (1 - 0.15) = 10880

7 0
2 years ago
Simplify <br> 2/5(a+b)+3/5(a+c)
Sergeu [11.5K]
Distribute 2/5 and 3/5 into the ():
2/5(a+b)+3/5(a+c)

2/5 a+ 2/5 b+3/5 a+ 3/5 c

combine the like terms:
2/5 a+3/5 a= 5/5 a --> 1a --> a

new simplified equation:
a+2/5 b+3/5 c
3 0
3 years ago
Read 2 more answers
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
3 years ago
7TH GRADE MATH!!! NEED ASAP
ludmilkaskok [199]

Answer:

l >= 60

Step-by-step explanation:

l greater than or equal to 60

8 0
3 years ago
Read 2 more answers
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