Plz help me ASAP. 11 points.

Mathematics

2 answers:

jekas [21]2 years ago

8 0

The answers are C and A

miss Akunina [59]2 years ago

6 0

Answer:

1.C 2.A

Step-by-step explanation:

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Send help please!! i want to complete it asap

Nadusha1986 [10]

It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6

So 4.2 (median) will lie in that interval 60-70 years.

7 0

2 years ago

Express the area of the entire rectangle.

Alexxandr [17]

2X+9
Combine like terms

4 0

2 years ago

Find the area of the shape below.

m_a_m_a [10]

Answer:

$A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2$

Step-by-step explanation:

I assume that it is a composed figure formed by a triangle and a square.Since you did not give the dimensions of the triangle and the dimensions of the square, I will giveyou a general explanation about how to solve this exercise.

The area of the shape will be the sum of the the area of the square and the area of the triangle.

Then, you need to remember that the area of a triangle can be calculated with the following formula:

$A_{triangle}=\frac{bh}{2}$