Chapter 3 skills and application
1 answer:
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Answer:
Option D
Explanation:
Given information
Bulk unit weight of 107.0 lb/cf
Water content of 7.3%,=0.073
Specific gravity of the soil solids is 2.62
Specifications
Dry unit weight is 113 lb/cf
Water content is 6%.
Volume of embankment is 440,000-cy
Borrow material
Embankment
Considering that the volume of embankment is inversely proportional to the dry unit weight
Therefore,
Therefore, volume of borrow material is 498594-cy
(b)
The weight of water in embankment is found by multiplying the moisture content and dry unit weight.
Assuming that all the specifications are achieved, weight of water in embankment=0.06*113=6.78 lb/cf
Since
The embankment requires water of 6.78*27*440000= 80546400 lb
Borrow materials’ water will also be 0.073*99.72041=7.27959 lb/cf
Borrow material requires water of 7.27959*27*498594=97998120 lb
Extra water between borrow material and embankment=97998120 lb-80546400 lb=17451720 lb
1 gallon is approximately hence
That's approximately 4.2 gallons