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almond37 [142]
3 years ago
5

You measure age (years), weight (pounds), and marital status (single, married, divorced, widowed) of 1400 women.  How many varia

bles did you measure?
A. 1 B. 2 C. 3 D. 4
Mathematics
1 answer:
Likurg_2 [28]3 years ago
5 0
C. 3

The age, weight, and marital status' are the variables. 
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Answer: Option C.  [0.95, 1.59].

Step-by-step explanation:

We know that the mean is:

M = 1.27

and the margin of error is:

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then the interval will be:

[M - e, M + e].= [1.27 - 0.32, 1.27 + 0.32].= [0.95, 1.59].

The correct option is C.

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What is the simplified expression for,
Nostrana [21]

Here are a few rules you need to know for this equation:

  • Multiplying exponents of the same base: x^m\times x^n=x^{m+n}
  • Dividing exponents of the same base: \frac{x^m}{x^n}=x^{m-n}
  • Turning a negative exponent to a positive one: x^{-m}=\frac{1}{x^m};\frac{1}{x^{-m}}=x^m

So this is our algebraic expression: \frac{3^{-4}\times 2^3\times 3^2}{2^4\times 3^{-3}}

Firstly, multiply 3^-4 and 3^2: \frac{3^{-4+2}\times 2^3}{2^4\times 3^{-3}}=\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}

Next, divide:

\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}=3^{-2-(-3)}2^{3-4}=3^12^{-1}

Next, turn the negative exponent into a positive one: 3^12^{-1}= \frac{3}{2}

<u>Your final answer is 3/2, or 1.5.</u>

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