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3 years ago

5

You measure age (years), weight (pounds), and marital status (single, married, divorced, widowed) of 1400 women. How many varia

bles did you measure?
A. 1 B. 2 C. 3 D. 4

1 answer:

Likurg_2 [28]3 years ago

5 0

C. 3

The age, weight, and marital status' are the variables.

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Translate the sentence into an equation.

Yakvenalex [24]

Answer:

The equation for this sentence is: 9 = 2(4y)

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3 years ago

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(3cosx-4sinx) + (3sinx+4cosx) = 5

Ksenya-84 [330]

(3 cos x-4 sin x)+(3sin x+4 cos x)=5
(3cos x+4cos x)+(-4sin x+3 sin x)=5
7 cos x-sin x=5
7cos x=5+sin x
(7 cos x)²=(5+sinx)²
49 cos²x=25+10 sinx+sin²x
49(1-sin²x)=25+10 sinx+sin²x
49-49sin²x=25+10sinx+sin²x
50 sin² x+10sinx-24=0

Sin x=[-10⁺₋√(100+4800)]/100=(-10⁺₋70)/100
We have two possible solutions:
sinx =(-10-70)/100=-0.8
x=sin⁻¹ (-0.8)=-53.13º (360º-53.13º=306.87)

sinx=(-10+70)/100=0.6
x=sin⁻¹ 0.6=36.87º

The solutions when 0≤x≤360º are: 36.87º and 306.87º.

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3 years ago

For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm

Paraphin [41]

The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>

<u />

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

and the base length of the second figure be, n = 7 mm

∴ The ratio of their areas will be

$(\frac{14 \ mm}{7 \ mm})^{2}$

$= \frac{196 \ mm^{2} }{49\ mm^{2} }$

$=\frac{4}{1}$

= 4:1

Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

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2 years ago

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3 years ago

What is the sum of the first five terms of a geometric series with a1=15 and r=1/3

Solnce55 [7]

Answer:

15, 5, 5/3, 5/9, 5/27

Step-by-step explanation:

Recall, that the general form of a geometric series is

a, ar, ar², ar³, .........

where a is the first term and r is the ratio

It is given that the first time is 15, hence a = 15

also given that ratio is 1/3

hence the first 5 terms are:

15, (15)(1/3), (15)(1/3)^2, (15)(1/3)^3, (15)(1/3)^4

simplifying each term gives

15, 5, 5/3, 5/9, 5/27

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3 years ago

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