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3 years ago

6

In this section please include the if then statements you develop during your lab activity these statement reflect your predicte

d outcomes for the experience

1 answer:

asambeis [7]3 years ago

3 0

Answer:

but for which activity donu need the answer and mention the question clearly

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In a free body diagram the weight is

torisob [31]

Answer:

Explanation:

a. WEIGHT: As we have seen, weight is the gravitational force exerted on an object by the Earth (or any other celestial body). If an object is near the Earth's surface and has mass, then the object has a weight. The magnitude of its weight is w = mg and its direction is toward the center of the Earth.

7 0

3 years ago

A 7.5 cm object is 14 cm from a concave lens, which has a focal length of –7 cm. Its image is 5 cm in front of the lens. What is

Rama09 [41]

Given conditions:
height of object = 7.5cmdistance of object from mirror = 14 cmfocus length = -7 cmimage distance = ?
Using mirror formula:
1/(focus length) = 1/(object distance) + 1/(image distance)
or, -1/7 = 1/14 + 1/(image distance)
or, image distance = -4.66cm (the image formed is a virtual image)

Also, magnification of image is:
image height /height of object = - image distance /object distance
or, image height = - image distance / object distance * height of object
or, image height = -(-4.66) / 14 * 7.5 = 2.49 = 3(nearest whole number)

3 0

3 years ago

Read 2 more answers

An ultrasound pulse used in medical imaging has a frequency of 5 MHz and a pulse width of 0.5 us. Ap- proximately how many osci

podryga [215]

At the frequency of 5 MHz, the period of the oscillations is 1/5meg. That's a period of 1/5 microsecond.

There are 5 full cycles in one full microsecond, and there are 2.5 full cycles in a 0.5 us pulse.

You'll have to decide for yourself how damped a pulse of 2.5 cycles is, because the parameters of the definition are corrupted in the question.

4 0

3 years ago

A wheel of radius R = 0.80 m is pulled by a rope looped around a frictionless axle. The total mass of the wheel and axle assembl

iragen [17]

Answer:

$\frac{K_T}{K_R}=\frac{600J}{188.63J}=3.18$

Explanation:

To find the rotational kinetic energy you first calculate the angular acceleration by using the following formula:

$\tau=I\alpha\\\\FR=I\alpha\\\\\alpha=\frac{FR}{I}$

F: force applied

R: radius of the wheel

I: moment of inertia

$\alpha=\frac{(120N)(0.80m)}{26.88kgm^2}=3.57\frac{rad}{s^2}$

With this value you calculate the angular velocity:

$\omega^2=\omega_o^2+2\alpha \theta\\$

you calculate how many radians the wheel run in 5.0m

$\theta=\frac{2\pi (0.8m)}{5.0m}=\approx1.00rad$

$\omega=\sqrt{2(3.57\frac{rad}{s^2})(1.00rad)}=2.67\frac{rad}{s}$

Next, you use the formula for the rotational kinetic energy:

$K_R=\frac{1}{2}I\omega^2=(26.88)(2.67)^2 J = 188.63J$

For the transnational kinetic energy you use the following equation:

$W=\Delta K_T$ (net work equals the change in the kinetic energy).

By replacing the you obtain:

$\Delta K_T=Fd=(120)(5.0)J=600J$

Finally, the ratio between translational rotational kinetic energy is:

$\frac{K_T}{K_R}=\frac{600J}{188.63J}=3.18$

hence, translational kinetic energy is three times the rotational kinetic energy.

6 0

3 years ago

What type of wave requires a medium to transfer energy?

Nonamiya [84]

Based on the given options above, the type of wave that requires a medium to transfer energy is MECHANICAL WAVE. The answer would be the third option. <span>Mechanical </span>waves<span> require a </span>medium<span> to travel through so that they can transmit </span>energy<span>. An example of this would be sound wave. Hope this helps.</span>

5 0

3 years ago

Read 2 more answers