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Andre45 [30]
3 years ago
9

Distances to nearby stars can be determined from _____.

Physics
2 answers:
AlexFokin [52]3 years ago
7 0
Distances to nearby stars can be determined from Stellar parallax. <span>Astronomers can measure a star's </span>position<span> once, and then again 6 months later and calculate the apparent change in </span>position<span>. The star's apparent motion is called stellar parallax. The distance d is measured in </span>parsecs<span> and the parallax angle p is measured in </span>arcseconds<span>.</span>
IrinaVladis [17]3 years ago
7 0

Answer:

The answer is  Stellar parallax.

Hope this helps.

Explanation:

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Using the right amount of significant figures, calculate the answer to the following problem, 15.33879 + 15.555
MAXImum [283]

Answer:

there are 7 significant figures

Explanation:

15.33879+15.555

=30.89379

there are 7 significant figures

mark me as brainliest plyyzzz

7 0
4 years ago
A large, metallic, spherical shell has no net charge. It is supported on an insulating stand and has a small hole at the top. A
tino4ka555 [31]

Answer:

(a) Negative Q

(b) Positive Q

Explanation:

Charge is the inherent property of matter due to the transference of electrons.

There are three methods of charging a body.

(i) Charging by friction: When two uncharged bodies rubbed together, then one body gets positive charged and the other is negatively charges it is due to the transference of electrons form one body to another.  

(ii) Conduction: when a charged body comes in contact with the another uncharged body, the uncharged body gets the same charge and the charge is distributed equally.

(iii) Induction: When a uncharged body keep near the charged body, the uncharged body gets the same amount of charge but opposite in sign.  

(a) When a small tack of charge Q is lowered into the hole, then due to the process of induction, the charge on the inner surface of the shell is - Q.

(b) Due to the process of conduction, the charge on the outer surface of the shell is Q.

7 0
3 years ago
describe an experiment to show how the frequency of a note emitted by a vibrating string depends on the tension of the string
mart [117]
Easy ! 

Take any musical instrument with strings ... a violin, a guitar, etc.

The length of the vibrating part of the strings doesn't change ...
it's the distance from the 'bridge' to the 'nut'.

Pluck any string.  Then, slightly twist the tuning peg for that string,
and pluck the string again.

Twisting the peg only changed the string's tension; the length
couldn't change.

-- If you twisted the peg in the direction that made the string slightly
tighter, then your second pluck had a higher pitch than your first one.

-- If you twisted the peg in the direction that made the string slightly
looser, then your second pluck had a lower pitch than the first one.
3 0
3 years ago
What happens to the charge on the conductive sphere when it is connected to a source of charge such as the electrostatic voltage
hichkok12 [17]

Answer and Explanation:

The charge on the conductive sphere spreads out non-uniformly over the surface of the sphere.

Normally, the charge on such spherical surface stay on this surface uniformly, but the presence of a voltage source tampers with that dynamic.

8 0
3 years ago
I appreciate the help on this physics question
Sidana [21]
Not enough information
3 0
3 years ago
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