Answer:
10 dumbbells
Explanation:
First we need to calculate the gravity on the moon.
0.166 x 9.8 m/s² = 1.627 m/s² (the gravity is 0.166 times the Earth's gravity)
Taking this acceleration due to gravity, and multiplying it by the mass of a single dumbbell.
F = m x a
F = (225 kg) x (1.627 m/s²)
F = 366.075 N (the amount of force exerted by the dumbbell)
Taking the weightlifter's total upward force and dividing it by the force exerted by one dumbbell, we can calculate the amount of dumbbells that can be carried.
(3750 N) / (366.075 N)
= 10.24 dumbbells (but since there cannot be a fraction of a dumbbell, the answer is <u>10 dumbbells</u>).
A) Kilograms per cubic meter. Every other option either contains pounds or feet, which are both units of measurement from the standard system, not the metric system.
Answer:
the magnitude of the force that the wire will experience = 1.8 N
Explanation:
The force on a current carrying wire placed in a magnetic field is :
F = Idl × B
where:
I = current flowing through the wire
dl = length of the wire
B = magnetic field
We can equally say that :
where : sin θ is the angle at which the orientation from the magnetic field to the wire occurs = 30°
Then;
Given that:
L = 20 cm = 0.2 m
I = 6 A
B = 3 T
θ = 30°
Then:
F = 3 × 6 × 0.2 sin 30°
F = 1.8 N
Therefore, the magnitude of the force that the wire will experience = 1.8 N
Did you get the answers the quiz??? If so please write out the answers in the comment section :)
Answer: E = 941738.537J
Explanation:
to begin,
given that the mass = 2320 pound = 1052.334 kg
Δh = 110 ft = 33.528 m
given that distance (d) = 1283 ft = 391.058 m
also the speed (v) is 65 mph = 29.058 m/s
force (F) = 87 pounds = 386.995 N
from our knowledge in work energy theory;
E = Fd + 1/2mv² + mgh
E = (386.995 × 391.058) + (1/2×1052.334×29.058²) + (1052.334×9.81×33.528)
E = 151337.491 + 444278.2 + 346122.84
E = 941738.537J
i hope this helps, cheers.
