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4 years ago

I need help ASAP.

Physics

2 answers:

Zina [86]4 years ago

7 0

Answer:

1. 2.23

2. 0.90

3. 0.28

aivan3 [116]4 years ago

4 0

1. Average time for the first 0.25 m: 2.23 s

Explanation:

The average time that it takes for the car to travel the first 0.25 m is given by the average of the first three measures, so:

$t=\frac{2.24s+2.21s+2.23s}{3}=2.227 s=2.23 s$

2. Average time to travel between 0.25 m and 0.50 m: 0.90 s

Explanation:

First of all, we need to calculate the time the car takes to travel between 0.25 m and 0.50 m for each trial:

t1 = 3.16 s - 2.24 s = 0.92 s

t2 = 3.08 s - 2.21 s = 0.87 s

t3 = 3.15 s - 2.23 s = 0.92 s

So, the average time is

$t=\frac{0.92 s + 0.87 s + 0.92 s}{3}=0.903 s=0.90 s$

3. Velocity in the second 0.25 m section: 0.28 m/s

Explanation:

The average velocity in the second 0.25 m section is equal to the ratio between the distance covered (0.25 m) and the average time taken (0.90 s):

$v=\frac{d}{t}=\frac{0.25 m}{0.90 s}=0.28 m/s$

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Resistors 1 and 2− R1 = 50 Ω , R2 = 90 Ω − are connected in series to a 6.0-V battery. Part APart complete What is the potential

kondor19780726 [428]

Answer:

Part A: The voltage across resistor R1 is approximately $\rm 2.1 \; V$ .

Part B: When the value of resistor R1 decreases, the current in this circuit will increase.

Part C: When the value of resistor R1 decreases, the voltage across resistor R1 will decrease.

Explanation:

Resistor R1 and and R2 are connected in series. That's equivalent to a single resistor of $R_1 + R_2 = 50 + 90 = 140\; \Omega$ . The voltage across the two resistor, combined, is equal to $\rm 6\; V$ . Hence by Ohm's Law, the current through the circuit will be equal to $\rm \dfrac{6\; V}{140\; \Omega} = \dfrac{3}{70}\; A$ .

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Keep in mind that if two resistors are connected in series,

$I(R_1) = I(\text{Circuit}) = I(R_2)$ .

The resistance of R1 decreases, while the current through it increases. Applying Ohm's Law on R1 won't give much useful information. However, since the resistance of R2 stays the same, the voltage across it will increase when its current increases (again by Ohm's Law.)

Again, since the two resistors are connected in series,

$V(R_1) + V(R_2) = V(\text{Circuit}) = \rm 6 \; V$ ,

when the voltage across R2 increases, the voltage across R1 will decrease.

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2 years ago

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nexus9112 [7]

Answer:

160 days

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Using the equation

rA^3/TA^2 = rB^3/TB^2

Where rA is radius of Moon A = R

TA is Time for moon A complete one orbit = 20 days

rB is radius of Moon B =4R

TB is Time for moon B complete one orbit = ?

Therefore

rA^3/TA^2 = rB^3/TB^2

R^3/20^2 = (4R)^3/TB^2

Cross multiply to solve for TB, then we have

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