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Svetllana [295]
3 years ago
7

What is the maximum number of electrons found in any energy level of the known elements? (Refer to the periodic table.) 112 32 8

6 92
Chemistry
2 answers:
Makovka662 [10]3 years ago
7 0

The answer is 32 electrons.

Fed [463]3 years ago
6 0

Answer:

32 electrons are the maximum electrons found in the N shell.

Explanation:

According to the periodic table, Maximum number of electrons in any energy level of known element is 32 which is found in N shell.

Each shell can contain fixed number of electrons. The first shell is the K shell that holds two electrons, the second shell that is L shell which holds eight electrons(2+6), The third shell is M shell which holds 18 electrons(2+6+10), and the fourth shell is N shell which holds the maximum number of electrons that is thirty two(2+6+10+14) electrons. The general formula is 2n^{2} electrons.

The outermost shell is called the valence shell and the electrons present in these shell are called valence electrons. Each shell consists of one or more subshells, and each subshell consists of one or more atomic orbitals.

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One solution has a formula C (n) H (2n) O (n) If this material weighs 288 grams, dissolves in weight 90 grams, the solution will
saw5 [17]

Explanation:

The given data is as follows.

Boiling point of water (T^{o}_{b}) = 100^{o}C = (100 + 273) K = 323 K,

Boiling point of solution (T_{b}) = 101.24^{o}C = (101.24 + 273) K = 374.24 K

Hence, change in temperature will be calculated as follows.

              \Delta T_{b} = (T_{b} - T^{o}_{b})

                           = 374.24 K - 323 K

                           = 1.24 K

As molality is defined as the moles of solute present in kg of solvent.

            Molality = \frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}

Let molar mass of the solute is x grams.

Therefore,   Molality = \frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}

                        m = \frac{288 g \times 1000}{x g \times 90}              

                          = \frac{3200}{x}

As,    \Delta T_{b} = k_{b} \times molality

                 1.24 = 0.512 ^{o}C/m \times \frac{3200}{x}

                       x = \frac{0.512 ^{o}C/m \times 3200}{1.24}

                          = 1321.29 g

This means that the molar mass of the given compound is 1321.29 g.

It is given that molecular formula is C_{n}H_{2n}O_{n}.

As, its empirical formula is CH_{2}O and mass is 30 g/mol. Hence, calculate the value of n as follows.

                n = \frac{\text{Molecular mass}}{\text{Empirical mass}}

                   = \frac{1321.29 g}{30 g/mol}

                   = 44 mol

Thus, we can conclude that the formula of given material is C_{44}H_{88}O_{44}.

4 0
3 years ago
What is the proper solution to the following equation? Answer with correct significant figures. (23.1 + 5.61 + 1.008) × 7.6134 ×
OleMash [197]

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Answer:

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Explanation:

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zlopas [31]

Answer:

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