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Gemiola [76]
3 years ago
7

A coil consists of 180 turns of wire. Each turn is a square of side d=30 cm, and a uniform magnetic field directed perpendicular

to the plane of the coil is turned on. If the field changes linearly from 0 to 1.22 T in 0.06s, what is the magnitude of the induced force in the coil while the field is changing?
Physics
1 answer:
alexira [117]3 years ago
8 0

Answer:

Emf induced i equal to 329.4 volt

Explanation:

Note : Here i think we have to find emf induced in the coil

Number of turns in the coil N= 180

Sides of square d = 30 cm = 0.3 m

So area of the square A=0.3\times 0.3=0.09m^2

Magnetic field is changes from 0 to 1.22 T

Therefore dB=1.22-0=1.22T

Time interval in changing the magnetic field dt = 0.06 sec

Induced emf is given by

e=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}

e=-180\times 0.09\times \frac{1.22}{0.06}=329.4volt

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Answer:

The current would be same in both situation.

Explanation:

Given that,

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We need to calculate the induced emf

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