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Gemiola [76]
3 years ago
7

A coil consists of 180 turns of wire. Each turn is a square of side d=30 cm, and a uniform magnetic field directed perpendicular

to the plane of the coil is turned on. If the field changes linearly from 0 to 1.22 T in 0.06s, what is the magnitude of the induced force in the coil while the field is changing?
Physics
1 answer:
alexira [117]3 years ago
8 0

Answer:

Emf induced i equal to 329.4 volt

Explanation:

Note : Here i think we have to find emf induced in the coil

Number of turns in the coil N= 180

Sides of square d = 30 cm = 0.3 m

So area of the square A=0.3\times 0.3=0.09m^2

Magnetic field is changes from 0 to 1.22 T

Therefore dB=1.22-0=1.22T

Time interval in changing the magnetic field dt = 0.06 sec

Induced emf is given by

e=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}

e=-180\times 0.09\times \frac{1.22}{0.06}=329.4volt

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Answer:

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Solved, can someone check it over! ​
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Sav [38]

The field strength needed to produce a 24.0 V peak emf is 0.73T.

To find the answer, we need to know about the expression of emf.

What's the expression of peak emf produced in a rotating rectangular loops?

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  • N= no. of turns of the loop, B= magnetic field, A= area of loop and w= angular frequency
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<h3>What's the magnetic field applied to the loop, when rectangular coil with 300 turns of dimensions 5.00 cm by 5.22 cm rotates at 400 rpm produce a 24.0 V peak emf?</h3>
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3 years ago
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Which of the following would have an effect on an object's mass?
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