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alekssr [168]
4 years ago
14

Which is an example of static friction?

Physics
1 answer:
nataly862011 [7]4 years ago
5 0

Answer:

static friction is developed between 2 surfaces in state of rest so i think answer is c.Even though the wheel is in motion, the patch of the tire in contact with the ground is stationary relative to the ground, so it is static rather than kinetic friction.

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Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 296o
Schach [20]

Explanation:

The given data is as follows.

       Temperature of metal = 296^{o}C = (296 + 273) K

                                            = 569 K

     Density of the metal = 8.85 g/cm^{3} = 8.85 \times 10^{-6} g/m^{3}      (as 1 cm^{3} = 10^{-6} m^{3})

     Atomic mass = 51.40 g/mol

    Vacancies = 9.19 \times 10^{23} m^{-3}

Formula to calculate the number of atomic sites is as follows.

           n = \frac{\rho \times N_{A}}{\text{atomic weight}}

              = \frac{8.85 \times 10^{-6} \times 6.022 \times 10^{23}}{51.40 g/mol}

              = 1.036 \times 10^{17} atom/m^{3}

Now, we will calculate the energy as follows.

                E = -KT \times ln (\frac{\text{no. of vacancies}}{\text{no. of atomic sites}})

where,    K = 8.62 \times 10^{-5}

         E = -8.62 \times 10^{-5} \times 569 K \times ln (\frac{9.19 \times 10^{23}}{1.036 \times 10^{17} atom/m^{3}})

               = 78.46 eV/atom

Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is 78.46 eV/atom.

6 0
4 years ago
From the edge of a cliff, a 0.41 kg projectile is launched with an initial kinetic energy of 1430 J. The projectile's maximum up
NemiM [27]

Answer:

v₀ₓ = 63.5 m/s

v₀y = 54.2 m/s

Explanation:

First we find the net launch velocity of projectile. For that purpose, we use the formula of kinetic energy:

K.E = (0.5)(mv₀²)

where,

K.E = initial kinetic energy of projectile = 1430 J

m = mass of projectile = 0.41 kg

v₀ = launch velocity of projectile = ?

Therefore,

1430 J = (0.5)(0.41)v₀²

v₀ = √(6975.6 m²/s²)

v₀ = 83.5 m/s

Now, we find the launching angle, by using formula for maximum height of projectile:

h = v₀² Sin²θ/2g

where,

h = height of projectile = 150 m

g = 9.8 m/s²

θ = launch angle

Therefore,

150 m = (83.5 m/s)²Sin²θ/(2)(9.8 m/s²)

Sin θ = √(0.4216)

θ = Sin⁻¹ (0.6493)

θ = 40.5°

Now, we find the components of launch velocity:

x- component = v₀ₓ = v₀Cosθ  = (83.5 m/s) Cos(40.5°)

<u>v₀ₓ = 63.5 m/s</u>

y- component = v₀y = v₀Sinθ  = (83.5 m/s) Sin(40.5°)

<u>v₀y = 54.2 m/s</u>

7 0
3 years ago
If a current of 2. 4 a is flowing in a wire of diameter 2. 0 mm, what is the average current density?
HACTEHA [7]

The average current density is 7.6 × 10⁵ A/m².

To calculate the current density current will be 2.4 A.

Diameter of a wire = 2mm.

The cross-sectional area of the wire is given by r = d/2

where r is the radius of the wire.  

Then, the cross-sectional area is = 0.00000314159265

                                                                   = 3.1 × 10⁻⁶ m².

<h3>What is average current density?</h3>

         Consider a current carrying conductor, the current density depends upon  the current flow in the conductor. If the current flow in the conductor will be high then the current density will also be high. Using the average current flowing through the conductor, the average current density will be found.

Average current density j = I / A Ampere/ meter².

By substituting the values in the formula,

             j = 2.4 / ( 3.1 × 10⁻⁶)

               = 7.6 × 10⁵ A/m².

Hence, the current density can be calculated.

Learn more about average current density,

brainly.com/question/3981451

#SPJ4

5 0
2 years ago
An airplane propeller rotates with an angular speed of 260 rad/s though what angul does the propeller rotate in 5.0s? Give your
ch4aika [34]

Answer:

1300 rad (74522^{\circ})

Explanation:

The angular speed of an object is the rate of change of angular position.

It is given by:

\omega=\frac{\theta}{t}

where

\omega is the angular speed

\theta is the angular displacement of the object

t is the time elapsed

For the propeller rotating in this problem, we have

\omega=260 rad/s is the angular speed

t = 5.0 s is the time elapsed

Therefore, the angular displacement is:

\theta=\omega t=(260)(5.0)=1300 rad

And since 2\pi rad = 360^{\circ}, the angle in degrees is

\theta=\frac{1300}{2\pi}(360)=74522^{\circ}

7 0
4 years ago
5. Define biodiversity, and list four ways that humans have a negative
jolli1 [7]
Biodiversity is the variety of life in the world or in a particular habitat or ecosystem. destruction, degradation and fragmentation of habitats. reduction of individual survival and reproductive rates through exploitation, pollution and introduction of alien species. Those are the negative impacts
6 0
4 years ago
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