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storchak [24]
3 years ago
12

Which of the following rules should be used to keep the appropriate distance between your vehicle and the vehicle in front of yo

u?
Physics
2 answers:
Kruka [31]3 years ago
8 0

Answer:

4-second following distance

alexandr402 [8]3 years ago
3 0
<span>The correct answer is C) Two-second rule.
</span><span>
</span><span>This means that a driver must maintain a distance that would take at least 2 seconds to cover, at the current speed of the car. This means that in case the car in front suddenly comes to a full stop, the driver of the car behind has 2 seconds react and hit his own brakes. A two-car length rule might be alright when driving at low speeds, but when going at high speeds (on a highway, for example), a two-car length can be covered in a fraction of a second, which means a sudden braking by the car in front would almost guarantee an accident.</span>
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In the picture below, a doctor is having a video conference with a patient. What might be a positive effect of the technology be
GarryVolchara [31]

Answer:

Sorry to say but where  is the photo???

The positive effect of technology being used might be using sethescope or checking BP rate if it is good.

Explanation:

6 0
3 years ago
If a 5kg ball is rolling to the left and has a momentum of -25kg*m/s what is the velocity (not just speed) of the ball
Anna71 [15]

Answer:

The velocity of the ball is 5 m/s to the left.

Explanation:

-25kg*m/s divided by 5 kg gives

speed of -5 m/s

The velocity of the ball is 5 m/s to the left.

5 0
3 years ago
On the moon, the acceleration of gravity is 1.6 m/s2. If an object has a
Amanda [17]

Answer:

5.1 kg

Explanation:

Its mass on the moon is 5.1 kg because mass is an intrinsic property of a material and does not change with location. Although, its weight might vary because its acceleration of gravity g is dependent on the mass M and radius r of the planet(in this case, moon) involved g = GM/r². Since weight W = mg is dependent o g, weight varies but mass remains constant.

4 0
3 years ago
Lightweight, vertically suspended spiral spring with a spring constant of 8.6 N / m is fitted with 64 g weight. The weight shall
alexandr1967 [171]

Answer:

Explanation:

Given that

Force constant k=8.6N/m

Weight =64g=64/1000=0.064kg

Extension is 45mm=45/1000= 0.045m

It will have it highest spend when the Potential energy is zero

Therefore energy in spring =change in kinetic energy

Ux=∆K.e

½ke² = ½mVf² — ½mVi²

Initial velocity is 0, Vi=0m/s

½ke² = ½mVf²

½ ×8.6 × 0.045² = ½ ×0.064 ×Vf²

0.0087075 = 0.032 Vf²

Then, Vf² = 0.0087075/0.032

Vf² = 0.2721

Vf=√0.2721

Vf= 0.522m/s

The time it will have this maximum velocity?

Using equation of motion

Vf= Vi + gr

0.522= 0+9.81t

t=0.522/9.81

t= 0.0532sec

t= 53.2 milliseconds

5 0
3 years ago
Can someone help with these
yaroslaw [1]

<em><u>One</u></em>

Givens

  • delta B = 0.20 T/s
  • A = 0.07 m^2
  • R = 3.5 ohms

Formula

Φ = ΔB*A

e = Φ

Solution (first part)

e = 0.2 * 0.07

e = 0.014 emf

Solution (second part)

i = e/R

i = 0.014 / 3.5

i = 4 * 10^-3

i = 4 ma

Answer

A

<em><u>Two</u></em>

Givens

N = 200 turns

Φ = 30 degrees

Delta B = 0.45 T/s

phi = 30 degrees

r = 0.06 meters

Formula

e = -N * delta B * A * Cos(phi)

Solution

e = -200 * 0.45 (pi r^2) * Cos(30)

e = - 200 * 0.45 * (3.14 * 0.06^2) * cos(30)

e = 0.881 emf

Answer

A

4 0
3 years ago
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