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andrezito [222]
3 years ago
11

Rank the ions in each set in order of decreasing size, and explain your ranking:

Chemistry
1 answer:
Valentin [98]3 years ago
5 0

Answer:

a) Se²⁻> S²⁻ > O²

b) Te²⁻ > I- >Cs+

c)  Cs+ > Ba²⁺ > Sr²⁺

Explanation:

(a) Se²⁻, S²⁻, O²⁻

In general, ionic radius decreases with increasing positive charge.

As the charge on the ion becomes more positive, there are fewer electrons.

The ion has a smaller radius. In general, ionic radius increases with increasing negative charge.

For ions of the same charge (e.g. in the same group) the size increases as we go down a group in the periodic table

Se²⁻> S²⁻ > O²

(b) Te²⁻, Cs⁺, I⁻

Te²⁻ > I- >Cs+

Te2- hast the biggest size, because of the double negative charge.

Cs+ has the smallest size since it has the most positive charge, compared to Te2- and I-.

(c) Sr²⁺, Ba²⁺, Cs⁺

Cs+ > Ba²⁺ > Sr²⁺

Cs+ has the biggest size, because its more downward (compared to Sr2+) and more to the left (compared) ot Ba2+.

Sr2+ has the smallest size because it's more upwords (compared to Cs+ and Ba2+)

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How do you think temperature will affect the rate of a chemical reaction?
Luba_88 [7]

Answer:

I could create a slower reaction because the particles might be moving slower due to the cold. if it was warm there will be a faster reaction. similar to the elements movements in solids and liquids.

8 0
3 years ago
Use the reaction 1₂(s) = 12(g), AH = 62.4 kJ/mol, AS = 0.145 kJ/(mol-K), for
Sati [7]

The Reaction is spontaneous when temperature is 430 K. Hence, Option (C) is correct.

<h3></h3><h3>What is Spontaneous reaction ?</h3>

Reactions are favorable when they result in a decrease in enthalpy and an increase in entropy of the system.

When both of these conditions are met, the reaction occurs naturally.

Spontaneous reaction is a reaction that favors the formation of products at the conditions under which the reaction is occurring.

According to Gibb's equation:

ΔG = ΔH - TΔS

ΔG = Gibbs free energy

ΔH = enthalpy change  = +62.4 kJ/mol

ΔS = entropy change  = +0.145 kJ/molK

T = temperature in Kelvin

  • ΔG  = +ve, reaction is non spontaneous
  • ΔG = -ve, reaction is spontaneous
  • ΔG   = 0, reaction is in equilibrium

ΔH - TΔS = 0 for reaction to be spontaneous

T = ΔH / ΔS

Here,

T = 500K

Thus the Reaction is spontaneous when temperature is 500 K.

Learn more about Gibbs free energy here ;

https://brainly.in/question/13372282

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3 0
2 years ago
Each incomplete reaction is a neutralization reaction. Match each equation with the salt formed. 1. H2SO4 + 2NH4OH → ? 2. 2NaOH
sergey [27]

1. H₂SO₄ + 2NH₄OH ⟶ (NH₄)₂SO₄ + 2H₂O


2. 2NaOH + H₂CO₃ ⟶ Na₂CO₃ + 2H₂O


3. HNO₃ + KOH ⟶ KNO₃ + H₂O


<em>Explanation</em>:

Acid + base ⟶ salt + water


Take the H from the acid and the OH from the base to get water.


Then, join what’s left to get the salt. Write the symbol for the metal first.


For example, in equation 3, take the H from HNO₃ and the OH from KOH.


Combining the remaining parts (NO₃ and K) to get the salt, KNO₃.


7 0
3 years ago
Read 2 more answers
Salt is poured from a container at 10 cm³ s-¹ and it formed a conical pile whose height at any time is 1/5 the radius of the abo
Romashka-Z-Leto [24]

Answer:

\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

Explanation:

Volume of a cone:

  • \displaystyle V=\frac{1}{3} \pi r^2 h

We have \displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec} and we want to find \displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ? when the height is 2 cm.

We can see in our equation for the volume of a cone that we have three variables: V, r, and h.

Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.

We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.

Plug this value for r into the volume formula:

  • \displaystyle V =\frac{1}{3} \pi (5h)^2 h  
  • \displaystyle V =\frac{1}{3} \pi \ 25h^3

Differentiate this equation with respect to time t.

  • \displaystyle \frac{dV}{dt}  =\frac{25}{3} \pi \ 3h^2 \ \frac{dh}{dt}
  • \displaystyle \frac{dV}{dt}  =25 \pi h^2 \ \frac{dh}{dt}

Plug known values into the equation and solve for dh/dt.

  • \displaystyle 10 = 25 \pi (2)^2  \ \frac{dh}{dt}
  • \displaystyle 10 = 100 \pi  \ \frac{dh}{dt}  

Divide both sides by 100π to solve for dh/dt.

  • \displaystyle \frac{10}{100 \pi} = \frac{dh}{dt}
  • \displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

The height of the cone is increasing at a rate of 1/10π cm per second.

7 0
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