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3 years ago

13

What is the SI unit for acceleration?

1 answer:

aivan3 [116]3 years ago

7 0

Answer: m/s^2 (metre per second square)

Explanation:

Acceleration is the rate of change in velocity per unit time. The standard unit of measurement for acceleration is m/s^2 (metre per second square).

It can be derived from:

Acceleration = velocity / Time

Acceleration = (metre per second / second)

Acceleration = metre per second square.

In short form, it is written as m/s^2

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If kc = 7.04 × 10-2 for the reaction: 2 hbr(g) ⇌h2(g) + br2(g), what is the value of kc for the reaction: 1/2 h2(g) + 1/2 br2 ⇌h

Kay [80]

At the first reaction when 2HBr(g) ⇄ H2(g) + Br2(g)
So Kc = [H2] [Br2] / [HBr]^2
7.04X10^-2 = [H2][Br] / [HBr]^2

at the second reaction when 1/2 H2(g) + 1/2 Br2 (g) ⇄ HBr
Its Kc value will = [HBr] / [H2]^1/2*[Br2]^1/2
we will make the first formula of Kc upside down:
1/7.04X10^-2 = [HBr]^2/[H2][Br2]
and by taking the square root:
∴ √(1/7.04X10^-2)= [HBr] / [H2]^1/2*[Br]^1/2
∴ Kc for the second reaction = √(1/7.04X10^-2) = 3.769

7 0

3 years ago

The natural process where the sun's energy is trapped by the atmosphere to make the Earth warm enough for life is known as

Juliette [100K]

The greenhouse effect captures the sun's energy and keeps the earth warm.

5 0

3 years ago

Helpppp meee plzzzzz

Firdavs [7]

Answer:

11 1/2 cm I think lol

Explanation:

it is in between the 11 and 12 mark

7 0

3 years ago

coldgirl [10]

Answer:

0.895 g/mL

Explanation:

Step 1: Given data

Mass of liquid Z (m): 2.763 lb

Volume of liquid Z (V): 5.93 cups

Step 2: Convert "m" to grams

We will use the relationship 1 lb = 453.59 g.

$2.763 lb \times \frac{453.59 g}{1lb} = 1,253g$

Step 3: Convert "V" to milliliters

We will use the relationship 1 cup = 236.59 mL.

$5.93cup \times \frac{236.59mL}{1cup} = 1.40 \times 10^{3} mL$

Step 4: Calculate the density of the liquid Z

The density (ρ) of the liquid Z is equal to its mass divided by its volume.

$\rho = \frac{m}{V} = \frac{1,253g}{1.40 \times 10^{3}mL } = 0.895 g/mL$

4 0

3 years ago

Place the following transitions of the hydrogen atom in order from longest to shortest wavelength of the photon emitted. Rank fr

gizmo_the_mogwai [7]

Answer:

7 to 4 (higher $\lambda$ )

5 to 3

3 to 2

4 to 2 (lower $\lambda$ )

Explanation:

We can use the Rydberg formula which relates the wavelength of the photon emissions to the principle quantum numbers involved in the transition:

$\frac{1}{\lambda}=R((\frac{1}{n_1^2})-(\frac{1}{n_2^2}))$

with $n_1$ final n, and $n_2$ initial n

evaluating for each transition:

7 to 4 $\frac{1}{\lambda} = R((\frac{1}{4^2})-(\frac{1}{7^2}))= R(1/16-1/49)=R(0.042)$

5 to 3 $\frac{1}{\lambda}= R(1/9-1/25)=R(0.071)$

4 to 2 $\frac{1}{\lambda}= R(1/4-1/16)=R(0.1875)$

3 to 2 $\frac{1}{\lambda}= R(1/4-1/9)=R(0.139)$

Note that the above formula is written for $\frac{1}{\lambda}$ , so lower $\frac{1}{\lambda}$ value obtained involves higher $\lambda$ .

So we should order from lower to higher $\frac{1}{\lambda}$

7 to 4 (higher $\lambda$ )

5 to 3

3 to 2

4 to 2 (lower $\lambda$ )

Note: Take into account that longer wavelength involves lower energy ( $E=\frac{hc}{\lambda}$ ).

3 0

3 years ago