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3 years ago

What is the SI unit for acceleration?

Chemistry

1 answer:

aivan3 [116]3 years ago

7 0

Answer: m/s^2 (metre per second square)

Explanation:

Acceleration is the rate of change in velocity per unit time. The standard unit of measurement for acceleration is m/s^2 (metre per second square).

It can be derived from:

Acceleration = velocity / Time

Acceleration = (metre per second / second)

Acceleration = metre per second square.

In short form, it is written as m/s^2

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The fire wood sends heat out in all directions. Warmed smoke filed air goes up the chimney. The outside of the metal fireplace g

maxonik [38]

Answer:

Convection

Explanation:

Convection is a mode of heat transfer that involves the actual movement of particles. In this case the particles are air particles.

Since hot air is less dense, it is pushed up by the denser cool air. This process may continue indefinitely and a convection current is set up.

5 0

3 years ago

Please hurry I’m stuck!!

MakcuM [25]

Answer:

Explanation:

C+O2=CO2

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4 years ago

Read 2 more answers

A chemical equation lists the atoms involved in a reaction?<br><br> A. True. B. False

salantis [7]

Answer:

a would be the correct answer

8 0

4 years ago

What takes place in organelles called chloroplasts

Vitek1552 [10]

Photosynthesis takes place in the chloroplasts, that is why the chloroplasts is green. The function of this organelles is to create energy into sugar from the sunlight.

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3 years ago

A BaSO4 slurry is ingested before the gastrointestinal tract is x-rayed because it is opaque to x-rays and defines the contours

NNADVOKAT [17]

Explanation:

The given reaction equation is as follows.

$BaSO_{4}(s) \rightleftharpoons Ba^{2+}(aq) + SO_{4}^{2-}(aq)$

The value of $\Delta G^{o}$ = 59.1 kJ/mol

We know that ,

$\Delta G^{o} = -RT ln K_{sp}$

or, $ln K_{sp} = -(\frac{\Delta G^{o}}{RT})
$

= -(\frac{59.1 kJ/mol}{(8.314 \times 10^{-3} kJ/mol.K \times 310 K))}[/tex]

= -22.93

or, $K_{sp} = e^{-22.93}$

= $1.1 \times 10^{-10}$

$K_{sp} = [Ba^{2+}][ SO_{4}^{2-}]$

Therefore, $[Ba^{2+}] =\sqrt{K_{sp}}$

= $\sqrt{ 1.1 \times 10^{-10}}$

= $1.05 \times 10^{-5} M$

Therefore, we can conclude that the value of $[Ba^{2+}]$ in the intestinal tract is $1.05 \times 10^{-5} M$ .

7 0

3 years ago