All categories

3 years ago

What are two factors that affect the function of enzymes

Chemistry

1 answer:

lapo4ka [179]3 years ago

4 0

Answer:

Temperature

Explanation:

Enzymes are organic catalysts that speeds up the rate of a chemical reaction. Their activities are affected by temperature and pH of the environment among other factors.

At extreme temperatures, enzymes can easily be denatured and they will cease to act.
At extremes of pH, they can also be adversely affect.

Enzymes generally have temperature and pH window for their activity.

You might be interested in

A cold front in New Hampshire in December will bring __________.

JulijaS [17]

i really dont know and im so so so so sorry

6 0

3 years ago

The 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning th

horrorfan [7]

Answer:

The enthalpy of reaction for the reaction of chlorine with ozone is -162.5 kJ.

Explanation:

$ClO ( g ) + O_3 ( g )\rightarrow Cl ( g ) + 2 O_2 ( g ),\Delta H^o_{1,rxn} =-122.8 kJ$ ..[1]

$2 O_3 ( g )\rightarrow 3O_2 ( g ),\Delta H^o_{2,rxn} = -285.3 kJ$ ..[2]

$O_3(g) + Cl(g)\rightarrow ClO (g)+O_2(g),\Delta H^o_{3,rxn}=?$ ..[3]

The enthalpy of reaction for the reaction of chlorine with ozone can be calculated by using Hess's law:

[2] - [1] = [3]

$\Delta H^o_{3,rxn}=\Delta H^o_{2,rxn}-\Delta H^o_{1,rxn}$

$=-285.3 kJ-(-122.8 kJ)=162.5 kJ$

The enthalpy of reaction for the reaction of chlorine with ozone is -162.5 kJ.

8 0

3 years ago

WHAT IS THE UNKNOWN METAL?

gavmur [86]

Answer:

The Unknown V was shiny and gray, but it was a lightweight metal. THE UNKNOWN METALS5V was aluminum, which has a density of 2.75 g/ml(Smith, 2019).

Explanation:

pls mark me as brainleast and folow me

6 0

3 years ago

Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:

posledela

Answer: The value of the equilibrium constant Kc for this reaction is 3.72

Explanation:

Equilibrium concentration of $HNO_3$ = $\frac{15.5g}{63g/mol\times 9.5L}=0.026M$

Equilibrium concentration of $NO$ = $\frac{16.6g}{30g/mol\times 9.5L}=0.058M$

Equilibrium concentration of $NO_2$ = $\frac{22.5g}{46g/mol\times 9.5L}=0.051M$

Equilibrium concentration of $H_2O$ = $\frac{189.0g}{18g/mol\times 9.5L}=1.10M$

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_c$